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anonymous
 5 years ago
solve for x 811x=5+4/3(2x) 4/3 is a fraction read 4 3rds
anonymous
 5 years ago
solve for x 811x=5+4/3(2x) 4/3 is a fraction read 4 3rds

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Owlfred
 5 years ago
Best ResponseYou've already chosen the best response.0Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when solving this, x becomes a decimal point not a whole number. is that what you are asked for?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just need to solve for x i know it will be a fraction, decimal, or whatever. This problem is driving me nuts!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got \[x=\frac{1}{37}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is the equation this? \[811x=5+\frac{4}{3}(2x) \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The first thing I would do is multiply both sides by 3 to get rid of the fraction.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats where im stuck what exactly do I multiply by 3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[811x=5+\frac{4}{3}(2x)\]\[\implies 3[811x] = 3[5+\frac{4}{3}(2x)]\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[811x=5+\frac{4}{3}(2x)\] distribute \[\frac{4}{3}\] so it equals to \[811x=5+\frac{8}{3}\frac{4}{3}x\] in one step i added \[(5+\frac{4}{3}) \] and 11x from left to right we get the following \[8=\frac{23}{3}\frac{37}{3}x\] \[subtract \frac{23}{3} \to both sides\] \[\frac{1}{3}=\frac{37}{3}x\] then divide.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That works too, but lots of fractions that way.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0polpak, i solved it this way. I like fractions.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yo dawg. I herd you liek fractions so I put some fractions in your fractions so you can divide when you divide.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Jwaddell, do you like fractions?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i hate them they cause issues like this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Jwaddell no matter what way you solve it. The answer is the same. if you want to. polpak or my self could help you solve by getting rid of fractions first.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, well if you multiply both sides of the equation you will rid yourself of the fraction.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0everyway ive tried comes out different

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[3[8−11x]=3[5+{4\over 3}(2−x)]\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So distribute the 3 on the left and you get: 24  33x = 15 + 4(2x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, so now distribute the 4 on the right hand side

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Perfect. Now combine the 15 + 8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok so you have \[24  33x = 23  4x\] So lets add 33x to both sides.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or is it 4+33 to = 29x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So we have 24 = 23 + 29x Now we subtract 23 from both sides.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Perhaps beehive should not like fractions so much ;p

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i guess so. I hurry a lot too much.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0very welcome. Be sure to review what we did so you can understand how to do it again in the future.
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