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anonymous

  • 5 years ago

solve for x 8-11x=5+4/3(2-x) 4/3 is a fraction read 4 3rds

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  1. Owlfred
    • 5 years ago
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    Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

  2. anonymous
    • 5 years ago
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    when solving this, x becomes a decimal point not a whole number. is that what you are asked for?

  3. anonymous
    • 5 years ago
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    i just need to solve for x i know it will be a fraction, decimal, or whatever. This problem is driving me nuts!

  4. anonymous
    • 5 years ago
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    i got \[x=\frac{-1}{37}\]

  5. anonymous
    • 5 years ago
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    steps??

  6. anonymous
    • 5 years ago
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    Is the equation this? \[8-11x=5+\frac{4}{3}(2-x) \]

  7. anonymous
    • 5 years ago
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    yes

  8. anonymous
    • 5 years ago
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    The first thing I would do is multiply both sides by 3 to get rid of the fraction.

  9. anonymous
    • 5 years ago
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    thats where im stuck what exactly do I multiply by 3?

  10. anonymous
    • 5 years ago
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    Everything.

  11. anonymous
    • 5 years ago
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    \[8-11x=5+\frac{4}{3}(2-x)\]\[\implies 3[8-11x] = 3[5+\frac{4}{3}(2-x)]\]

  12. anonymous
    • 5 years ago
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    \[8-11x=5+\frac{4}{3}(2-x)\] distribute \[\frac{4}{3}\] so it equals to \[8-11x=5+\frac{8}{3}-\frac{4}{3}x\] in one step i added \[(5+\frac{4}{3}) \] and -11x from left to right we get the following \[8=\frac{23}{3}-\frac{37}{3}x\] \[subtract \frac{23}{3} \to both sides\] \[\frac{1}{3}=-\frac{37}{3}x\] then divide.

  13. anonymous
    • 5 years ago
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    That works too, but lots of fractions that way.

  14. anonymous
    • 5 years ago
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    polpak, i solved it this way. I like fractions.

  15. anonymous
    • 5 years ago
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    ok...

  16. anonymous
    • 5 years ago
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    Yo dawg. I herd you liek fractions so I put some fractions in your fractions so you can divide when you divide.

  17. anonymous
    • 5 years ago
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    ;)

  18. anonymous
    • 5 years ago
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    :)

  19. anonymous
    • 5 years ago
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    Jwaddell, do you like fractions?

  20. anonymous
    • 5 years ago
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    i hate them they cause issues like this

  21. anonymous
    • 5 years ago
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    Jwaddell no matter what way you solve it. The answer is the same. if you want to. polpak or my self could help you solve by getting rid of fractions first.

  22. anonymous
    • 5 years ago
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    Ok, well if you multiply both sides of the equation you will rid yourself of the fraction.

  23. anonymous
    • 5 years ago
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    everyway ive tried comes out different

  24. anonymous
    • 5 years ago
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    multiply by 3.

  25. anonymous
    • 5 years ago
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    \[3[8−11x]=3[5+{4\over 3}(2−x)]\]

  26. anonymous
    • 5 years ago
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    So distribute the 3 on the left and you get: 24 - 33x = 15 + 4(2-x)

  27. anonymous
    • 5 years ago
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    got that

  28. anonymous
    • 5 years ago
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    Ok, so now distribute the 4 on the right hand side

  29. anonymous
    • 5 years ago
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    What have you got?

  30. anonymous
    • 5 years ago
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    24-33x=15+8-4x

  31. anonymous
    • 5 years ago
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    Perfect. Now combine the 15 + 8

  32. anonymous
    • 5 years ago
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    k

  33. anonymous
    • 5 years ago
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    23

  34. anonymous
    • 5 years ago
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    Ok so you have \[24 - 33x = 23 - 4x\] So lets add 33x to both sides.

  35. anonymous
    • 5 years ago
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    yes

  36. anonymous
    • 5 years ago
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    24=23-37x???

  37. anonymous
    • 5 years ago
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    Nope.. -4x + 33x = ?

  38. anonymous
    • 5 years ago
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    or is it -4+33 to = 29x

  39. anonymous
    • 5 years ago
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    yes

  40. anonymous
    • 5 years ago
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    k

  41. anonymous
    • 5 years ago
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    So we have 24 = 23 + 29x Now we subtract 23 from both sides.

  42. anonymous
    • 5 years ago
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    so then 1=29x

  43. anonymous
    • 5 years ago
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    Right!

  44. anonymous
    • 5 years ago
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    1/29=x

  45. anonymous
    • 5 years ago
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    Yep

  46. anonymous
    • 5 years ago
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    Perhaps beehive should not like fractions so much ;p

  47. anonymous
    • 5 years ago
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    i guess so. I hurry a lot too much.

  48. anonymous
    • 5 years ago
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    thank you!!!!

  49. anonymous
    • 5 years ago
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    very welcome. Be sure to review what we did so you can understand how to do it again in the future.

  50. anonymous
    • 5 years ago
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    i will

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