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when solving this, x becomes a decimal point not a whole number. is that what you are asked for?

i got \[x=\frac{-1}{37}\]

steps??

Is the equation this?
\[8-11x=5+\frac{4}{3}(2-x) \]

yes

The first thing I would do is multiply both sides by 3 to get rid of the fraction.

thats where im stuck what exactly do I multiply by 3?

Everything.

\[8-11x=5+\frac{4}{3}(2-x)\]\[\implies 3[8-11x] = 3[5+\frac{4}{3}(2-x)]\]

That works too, but lots of fractions that way.

polpak, i solved it this way. I like fractions.

ok...

;)

:)

Jwaddell, do you like fractions?

i hate them they cause issues like this

Ok, well if you multiply both sides of the equation you will rid yourself of the fraction.

everyway ive tried comes out different

multiply by 3.

\[3[8−11x]=3[5+{4\over 3}(2−x)]\]

So distribute the 3 on the left and you get:
24 - 33x = 15 + 4(2-x)

got that

Ok, so now distribute the 4 on the right hand side

What have you got?

24-33x=15+8-4x

Perfect. Now combine the 15 + 8

23

Ok so you have
\[24 - 33x = 23 - 4x\]
So lets add 33x to both sides.

yes

24=23-37x???

Nope.. -4x + 33x = ?

or is it -4+33 to = 29x

yes

So we have 24 = 23 + 29x
Now we subtract 23 from both sides.

so then 1=29x

Right!

1/29=x

Yep

Perhaps beehive should not like fractions so much ;p

i guess so. I hurry a lot too much.

thank you!!!!

very welcome. Be sure to review what we did so you can understand how to do it again in the future.

i will