solve for x 8-11x=5+4/3(2-x) 4/3 is a fraction read 4 3rds

- anonymous

solve for x 8-11x=5+4/3(2-x) 4/3 is a fraction read 4 3rds

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- anonymous

when solving this, x becomes a decimal point not a whole number. is that what you are asked for?

- anonymous

i just need to solve for x i know it will be a fraction, decimal, or whatever. This problem is driving me nuts!

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## More answers

- anonymous

i got \[x=\frac{-1}{37}\]

- anonymous

steps??

- anonymous

Is the equation this?
\[8-11x=5+\frac{4}{3}(2-x) \]

- anonymous

yes

- anonymous

The first thing I would do is multiply both sides by 3 to get rid of the fraction.

- anonymous

thats where im stuck what exactly do I multiply by 3?

- anonymous

Everything.

- anonymous

\[8-11x=5+\frac{4}{3}(2-x)\]\[\implies 3[8-11x] = 3[5+\frac{4}{3}(2-x)]\]

- anonymous

\[8-11x=5+\frac{4}{3}(2-x)\] distribute \[\frac{4}{3}\]
so it equals to \[8-11x=5+\frac{8}{3}-\frac{4}{3}x\]
in one step i added \[(5+\frac{4}{3}) \] and -11x from left to right
we get the following
\[8=\frac{23}{3}-\frac{37}{3}x\]
\[subtract \frac{23}{3} \to both sides\]
\[\frac{1}{3}=-\frac{37}{3}x\]
then divide.

- anonymous

That works too, but lots of fractions that way.

- anonymous

polpak, i solved it this way. I like fractions.

- anonymous

ok...

- anonymous

Yo dawg. I herd you liek fractions so I put some fractions in your fractions so you can divide when you divide.

- anonymous

;)

- anonymous

:)

- anonymous

Jwaddell, do you like fractions?

- anonymous

i hate them they cause issues like this

- anonymous

Jwaddell no matter what way you solve it. The answer is the same. if you want to. polpak or my self could help you solve by getting rid of fractions first.

- anonymous

Ok, well if you multiply both sides of the equation you will rid yourself of the fraction.

- anonymous

everyway ive tried comes out different

- anonymous

multiply by 3.

- anonymous

\[3[8âˆ’11x]=3[5+{4\over 3}(2âˆ’x)]\]

- anonymous

So distribute the 3 on the left and you get:
24 - 33x = 15 + 4(2-x)

- anonymous

got that

- anonymous

Ok, so now distribute the 4 on the right hand side

- anonymous

What have you got?

- anonymous

24-33x=15+8-4x

- anonymous

Perfect. Now combine the 15 + 8

- anonymous

k

- anonymous

23

- anonymous

Ok so you have
\[24 - 33x = 23 - 4x\]
So lets add 33x to both sides.

- anonymous

yes

- anonymous

24=23-37x???

- anonymous

Nope.. -4x + 33x = ?

- anonymous

or is it -4+33 to = 29x

- anonymous

yes

- anonymous

k

- anonymous

So we have 24 = 23 + 29x
Now we subtract 23 from both sides.

- anonymous

so then 1=29x

- anonymous

Right!

- anonymous

1/29=x

- anonymous

Yep

- anonymous

Perhaps beehive should not like fractions so much ;p

- anonymous

i guess so. I hurry a lot too much.

- anonymous

thank you!!!!

- anonymous

very welcome. Be sure to review what we did so you can understand how to do it again in the future.

- anonymous

i will

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