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anonymous

  • 5 years ago

lim x -> 0 (x-1)/(3sin(x) - cos(x))

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  1. anonymous
    • 5 years ago
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    evaluate the limit of the trigonomoteric limit

  2. myininaya
    • 5 years ago
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    (0-1)/(3sin(0)-cos(0)) =-1/(3*0-1) =-1/(0-1) =-1/(-1) =1

  3. anonymous
    • 5 years ago
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    we cant substitute first

  4. myininaya
    • 5 years ago
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    the function is continuous at x=0 so yes we can

  5. anonymous
    • 5 years ago
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    :s ok i guess

  6. anonymous
    • 5 years ago
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    so thats not the same as lim x-> 0 2sin (3x)/ 5x which would be equal to 6/5?

  7. myininaya
    • 5 years ago
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    this function is discontinuous at x=0 we can manipulate this function though to see what happens as x->0 remember sinx/x->1 as x->0 so 3/3*2sin(3x)/5x=6/5*sin(3x)/3x=6/5*(1) since sin(3x)/3x->1 as x->0

  8. anonymous
    • 5 years ago
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    ok thank you i get it

  9. anonymous
    • 5 years ago
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    i forgot about continuity

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