anonymous
  • anonymous
Evaluate the following limit: lim x -> 1 sin (x-1)/ (x^2 + x -2) i got 1/3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Did you use l'Hopital?
anonymous
  • anonymous
we didnt learn it yet so we cant use it
anonymous
  • anonymous
I think you have to. You have 0 over 0 here.

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More answers

myininaya
  • myininaya
sin(x-1)/(x-1)(x+2) sin(x-1)/(x-1)->1 as x->1 so now we have 1/(x+2)->1/3 since x->1
anonymous
  • anonymous
this is what i did lim x-> 1 sin (x-1)/(x-1)(x+2) sin (x-1)/x-1 x 1/x+2 then substitute the lim in 1x 1/3 1/3
myininaya
  • myininaya
remember sinx/x->1 as x->0 so sin(x-1)/(x-1)->1 as x->1
anonymous
  • anonymous
sin(x-1)/(x-1)->1 as x->1 using l'Hopital?
anonymous
  • anonymous
oh yay myiniaya! we did the same thing
myininaya
  • myininaya
no using sinx/x->1 as x->0
anonymous
  • anonymous
yes, but how do you evaluate that limit without l'hopital?
myininaya
  • myininaya
we could use the squeeze theorem to show sinx/x->1 as x->0
anonymous
  • anonymous
I mean someone could tell you, but they would have had to do it. Or I guess squeeze theorem. But either way I'd like to see more of a justification there.
myininaya
  • myininaya
i could totally prove this sinx/x thing give me a sec and i will post
anonymous
  • anonymous
the lim is x-> 1 though
anonymous
  • anonymous
I know it is.
anonymous
  • anonymous
I just don't know that you know it is ;p
myininaya
  • myininaya
what
anonymous
  • anonymous
lol so i cant use the squeeze theorem
anonymous
  • anonymous
what? You have to use squeeze theorem.
myininaya
  • myininaya
lol what polpak what are you saying to me
myininaya
  • myininaya
do you guys want me to prove it or not?
anonymous
  • anonymous
no. I'm good. I was just saying that purp should give some justification when he uses it in his argument
myininaya
  • myininaya
ok
anonymous
  • anonymous
then isnt my answer right
anonymous
  • anonymous
it is right.
myininaya
  • myininaya
yes it is i think polpak just wants you to understand why sinx/x->1 as x->0
anonymous
  • anonymous
i am a girl thank you very much
anonymous
  • anonymous
so whats the problem?
anonymous
  • anonymous
'he' is not gender specific.
myininaya
  • myininaya
im a girl too. what do you mean you are a girl? are you saying we can't do math as well as guys?
anonymous
  • anonymous
she means I said 'he' before and she was correcting my use of that pronoun
myininaya
  • myininaya
oh lol sorry
anonymous
  • anonymous
but 'he' is correct usage when you don't know the person's gender.
myininaya
  • myininaya
no i don't believe you polpak
anonymous
  • anonymous
why? exactly is that because my teacher did this long proof on the board
anonymous
  • anonymous
it's true! she is gender specific. he is not.
myininaya
  • myininaya
don't make me growl i do not want to be referred to as a he
anonymous
  • anonymous
but purple is girly anyway were here for the math lol
anonymous
  • anonymous
Well now that I know you are a woman I will refer to you as she if it makes you feel better =)
anonymous
  • anonymous
http://en.wikipedia.org/wiki/Gender-neutral_pronoun
myininaya
  • myininaya
no im here to defend my sex
myininaya
  • myininaya
lol
anonymous
  • anonymous
no i mean why is sinx/x = 1
anonymous
  • anonymous
no i mean why is sinx/x = 1
myininaya
  • myininaya
i will make you a proof k
anonymous
  • anonymous
because it is. You can prove that it is using the sqeeze theorem or l'hopitals.
anonymous
  • anonymous
this website is freezing please dont type fast we'll confuse ourselves
anonymous
  • anonymous
It gets laggy when the question gets too long.
anonymous
  • anonymous
ok thank you gents {i assume} will you help me with my other questions
anonymous
  • anonymous
Of course.
myininaya
  • myininaya
1 Attachment
myininaya
  • myininaya
i made you a pretty proof its posted in the attachment
anonymous
  • anonymous
i'll post it somewhere else to cut the lag
anonymous
  • anonymous
aww :$ thank you
myininaya
  • myininaya
does it make sense alittle?

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