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anonymous

  • 5 years ago

Evaluate the following limit: lim x -> 1 sin (x-1)/ (x^2 + x -2) i got 1/3

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  1. anonymous
    • 5 years ago
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    Did you use l'Hopital?

  2. anonymous
    • 5 years ago
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    we didnt learn it yet so we cant use it

  3. anonymous
    • 5 years ago
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    I think you have to. You have 0 over 0 here.

  4. myininaya
    • 5 years ago
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    sin(x-1)/(x-1)(x+2) sin(x-1)/(x-1)->1 as x->1 so now we have 1/(x+2)->1/3 since x->1

  5. anonymous
    • 5 years ago
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    this is what i did lim x-> 1 sin (x-1)/(x-1)(x+2) sin (x-1)/x-1 x 1/x+2 then substitute the lim in 1x 1/3 1/3

  6. myininaya
    • 5 years ago
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    remember sinx/x->1 as x->0 so sin(x-1)/(x-1)->1 as x->1

  7. anonymous
    • 5 years ago
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    sin(x-1)/(x-1)->1 as x->1 using l'Hopital?

  8. anonymous
    • 5 years ago
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    oh yay myiniaya! we did the same thing

  9. myininaya
    • 5 years ago
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    no using sinx/x->1 as x->0

  10. anonymous
    • 5 years ago
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    yes, but how do you evaluate that limit without l'hopital?

  11. myininaya
    • 5 years ago
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    we could use the squeeze theorem to show sinx/x->1 as x->0

  12. anonymous
    • 5 years ago
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    I mean someone could tell you, but they would have had to do it. Or I guess squeeze theorem. But either way I'd like to see more of a justification there.

  13. myininaya
    • 5 years ago
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    i could totally prove this sinx/x thing give me a sec and i will post

  14. anonymous
    • 5 years ago
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    the lim is x-> 1 though

  15. anonymous
    • 5 years ago
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    I know it is.

  16. anonymous
    • 5 years ago
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    I just don't know that you know it is ;p

  17. myininaya
    • 5 years ago
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    what

  18. anonymous
    • 5 years ago
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    lol so i cant use the squeeze theorem

  19. anonymous
    • 5 years ago
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    what? You have to use squeeze theorem.

  20. myininaya
    • 5 years ago
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    lol what polpak what are you saying to me

  21. myininaya
    • 5 years ago
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    do you guys want me to prove it or not?

  22. anonymous
    • 5 years ago
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    no. I'm good. I was just saying that purp should give some justification when he uses it in his argument

  23. myininaya
    • 5 years ago
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    ok

  24. anonymous
    • 5 years ago
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    then isnt my answer right

  25. anonymous
    • 5 years ago
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    it is right.

  26. myininaya
    • 5 years ago
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    yes it is i think polpak just wants you to understand why sinx/x->1 as x->0

  27. anonymous
    • 5 years ago
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    i am a girl thank you very much

  28. anonymous
    • 5 years ago
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    so whats the problem?

  29. anonymous
    • 5 years ago
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    'he' is not gender specific.

  30. myininaya
    • 5 years ago
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    im a girl too. what do you mean you are a girl? are you saying we can't do math as well as guys?

  31. anonymous
    • 5 years ago
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    she means I said 'he' before and she was correcting my use of that pronoun

  32. myininaya
    • 5 years ago
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    oh lol sorry

  33. anonymous
    • 5 years ago
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    but 'he' is correct usage when you don't know the person's gender.

  34. myininaya
    • 5 years ago
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    no i don't believe you polpak

  35. anonymous
    • 5 years ago
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    why? exactly is that because my teacher did this long proof on the board

  36. anonymous
    • 5 years ago
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    it's true! she is gender specific. he is not.

  37. myininaya
    • 5 years ago
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    don't make me growl i do not want to be referred to as a he

  38. anonymous
    • 5 years ago
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    but purple is girly anyway were here for the math lol

  39. anonymous
    • 5 years ago
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    Well now that I know you are a woman I will refer to you as she if it makes you feel better =)

  40. anonymous
    • 5 years ago
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    http://en.wikipedia.org/wiki/Gender-neutral_pronoun

  41. myininaya
    • 5 years ago
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    no im here to defend my sex

  42. myininaya
    • 5 years ago
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    lol

  43. anonymous
    • 5 years ago
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    no i mean why is sinx/x = 1

  44. anonymous
    • 5 years ago
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    no i mean why is sinx/x = 1

  45. myininaya
    • 5 years ago
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    i will make you a proof k

  46. anonymous
    • 5 years ago
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    because it is. You can prove that it is using the sqeeze theorem or l'hopitals.

  47. anonymous
    • 5 years ago
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    this website is freezing please dont type fast we'll confuse ourselves

  48. anonymous
    • 5 years ago
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    It gets laggy when the question gets too long.

  49. anonymous
    • 5 years ago
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    ok thank you gents {i assume} will you help me with my other questions

  50. anonymous
    • 5 years ago
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    Of course.

  51. myininaya
    • 5 years ago
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    1 Attachment
  52. myininaya
    • 5 years ago
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    i made you a pretty proof its posted in the attachment

  53. anonymous
    • 5 years ago
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    i'll post it somewhere else to cut the lag

  54. anonymous
    • 5 years ago
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    aww :$ thank you

  55. myininaya
    • 5 years ago
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    does it make sense alittle?

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