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anonymous
 5 years ago
Evaluate the following limit:
lim x>0 sin(x) cos (x)/x
anonymous
 5 years ago
Evaluate the following limit: lim x>0 sin(x) cos (x)/x

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 0}sinxcosx/x=\lim_{x \rightarrow 0}sinx/x*\lim_{x \rightarrow 0}\cos(x)\] both limits are 1. So the whole limit is 1

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0sinx/x>1 cosx is left over but also goes to 1 both as x>0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no the limit exists, it is 1. cos(x) goes to 1 and sinx/x goes to 1 as well

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because cos x / x = 1/0... no?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0lol can you not write the function as sinx/x *cosx?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you aren't plugging in 0 though it's a limit

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there are limits that have a division by 0 and still exist it is about infinitesimal behavior

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i wrote sinx / x * cosx / x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is not x^2 on the bottom

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0(5*6)/(5)=6 but by what you say we can do or suppose to do 5/5*6/5=6/5

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0i mean (5*6)/5=5/5*6=1*6=6 and you say (5*6)/5=5/5*6/5=6/5 is that what you are saying this second line right here?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i seperate the fraction

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0i think you are thinking about addition on fractions (a+b)/c=a/c+b/c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry guys the lag go the best of me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i mean the 2nd line what you di

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0you can't do (5*6)/5=5/5*6/5 but you do (5*6)/5=5/5*6 or 5/6*5=6

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0so we can write sinx/x*cosx?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no sin x/x * cox x /x

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0but you just said we can't do (5*6)/5=5/5*6/5

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0(sinx*cosx)/x=sinx/x * cosx

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0or =cosx/x * sinx ( it does us no good to write it like this though)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so how do i work it? i am confused

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0write (sinx*cosx)/x=sinx/x*cosx where does sinx/x go to as x gets closer to 1?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0as x gets closer to 0?*

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you know how to use latex here because i dont understand what you typed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the answer is 1 i dont undertstand why it cant be done the way i did it i understand what you typed

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0so you still don't understand why we can't do: \[\frac{\sin(x)\cos(x)}{x}=\frac{\sin(x)}{x}\frac{\cos(x)}{x}?\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0we don't have x^2 on bottom? we only have x

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{5*6}{5}\neq \frac{5}{5}*\frac{6}{5}\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0do you agree with this statement?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{5*6}{5}=\frac{5}{5}*6=6\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 0} \frac{\sin(x)\cos(x)}{x}=\lim_{x \rightarrow 0}\frac{\sin(x)}{x}*\cos(x)\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0\[=\lim_{x \rightarrow 0}\frac{\sin(x)}{x}*\lim_{x \rightarrow 0}\cos(x)=1*1=1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i guess i gotta recheck my fractions thank you so much i have 1 more question if your not busy can you help me with that please

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0i gotta pee i might return

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol ok THANK YOU SO MUCH
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