Solve the formula for x:

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- anonymous

Solve the formula for x:

- schrodinger

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- anonymous

Which formula brah.

- anonymous

That might help, haha.

- anonymous

\[T=5((x-2)/4)+1\]

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## More answers

- anonymous

obviously the x-2 is over the 4 I just dunno how to write that on here

- anonymous

is T just another variable, or what?
It should be 4((T-1)/5)+2=x

- anonymous

Makes sense how I did it, or do you want me to explain?

- anonymous

T is just the equaling variable

- anonymous

whoa how did you get that???

- anonymous

Okayyy. So you have the T=whatever, right. You know that if you subtract one from both sides you're effectively doing nothing, right? So it becomes T-1=4(x-2)/5
Then you can divide both sides by 5 to rid yourself of the 5 on the x's side. That gives you (T-1)/5)=4(x-2)
then you multiply both sides by 4. and you get 4(T-1)/5

- anonymous

and so on. Makes sense? If you still have questions I can try to answer it better on msn or something.

- anonymous

you skips a bunch of steps. why did you switch the places of the 4 & 5?

- anonymous

oh did I, that was probably a typo. I'll type it out in full. Give me a second.

- anonymous

T=5((x−2)/4)+1
T-1=5((x−2)/4)
(T-1)/5=((x−2)/4)
4(T-1)/5=x-2
(4(T-1)/5)-2=x

- anonymous

I'm just unsure what you don't understand :) sorry, if you still don't get it I'll try again

- anonymous

well why dont you multiply 5 into (x-2) to = 5x-10?

- anonymous

You do. Except that's expanding the equation and it would make it harder to work with. If you did that you'd have to then do
5x/4-10/4+1=T
5x-6/4=T
5x=T+3/2
x=(T+3/2)/5

- anonymous

both should be correct... I think

- anonymous

where did the 4 go under the 5x? shouldnt it be 5x-10 all over 4?

- anonymous

Yeah. 4x/4-10/4. I just split it into two fractions to make it more malleable. Math is so hard to explain typing ):

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