T=5((x−2)/4)+1

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T=5((x−2)/4)+1

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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and solve for what?
x
sorry

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steps please.
I answered that.
i still dont understand it though
Do you know why you can equate two sides of an equation?
\[x=\frac{2}{5} (3+2 T) \]
i know about the order of operations thats not what I need to know.
i need all steps from beginning please!
Robtobey how did you get your solution?
there is no 10 in the equation...
*facepalm*
jwaddell your equation is little confusing. if solve for x. then x would equal some number with T in them.
yes i know
if you solve it that way then. \[x=(4(\frac{T}{5})-1)+2\]
WOW the T is throwing me off
first, distribute 5 to (x-2)/2 sop, we get (5x-10)/4 + 1=0, if T=0 then, the LCD is 4, so it will become (5x-10+4)/4=0 5x-6=0 5x=6 x=1.2
if T=0 then x=1.1999999999
or, if the value of T is not given, then, x=(4T+6)/5
Pat yours makes sense thanks!
you are welcome.
thanks for the medal.
no prob you wanna help me with one more?
sure.
\[A= (3m+2)/(m-1)\]
solve for m
m=(A(m-1)-2)/3
that is not right pat. since the other m is there also.
yeah, i had a mistake, i did not see it. thanks
m=(A+2)/(A-3) what did you get?
can u show me the steps too please
m=(-2-A)/3-A
(3m+2)/(m-1)=A, then cross multiply, you will get 3m+2=Am-A 3m-Am=-2-A m(3-A)=-2-A m=(-2-A)/(3-A)
would't it be Am-3m=2-A???
or actually Am-3m-2+A
jwaddell06, Do you still want to see how the first problem was solved, now that the dust has settled?
\[T=\frac{5 (x-2)}{4}+1 \]\[T-1=\frac{5 (x-2)}{4} \]\[4(T-1)=5 (x-2)\]\[\frac{4(T-1)}{5}=(x-2)\]\[\frac{4(T-1)}{5}+2=x \]Simplify the left side to obtain:\[\frac{2}{5} (2 T+3)=x \]
now why wouldnt you multiply the 5 into x-2
The object is to isolate x on the right hand equation side. The easiest path for me was to divide by 5 leaving x - 2. When +2 is added to each side, x is left alone.
That makes sense a little but i thought whenever you were given something like 5(x-2) you were supposed to make it 5x-10 then isolate x from there.
Well the final result should be OK. Give me a minute to work it out.
\[4(T-1)=5 (x-2) \]\[4(T-1)=5 x-10 \]\[4(T-1)+10=5 x \]\[\frac{4(T-1)+10}{5}=x \]\[\frac{2}{5} (2 T+3)=x \]
ok i get it up to the last part how do you get 2/5(2T+3)
\[\frac{4(T-1)+10}{5} \]Simplify the numerator\[\frac{(4 T+6)}{5}\]Factor the numerator\[\frac{(2 (2 T+3))}{5}=x \]Factor the expresssion\[\frac{2}{5} (2 T+3) \] I actually use Mathematica to do the calculations and had to resolve the problem by hand to answer you follow up questions.
what is mathematica??
I have to break off for about 10 minutes. Will be back then to answer any other questions.
i dont understand how to simplify the numerator like that. sorry its been 10 years since I did algebra if not longer.
what is mathematica?? Here is an introductory video. http://www.wolfram.com/solutions/education/students/
Simplification is a nicety, but not required to present a valid problem solution.
You're still looking at this .-.

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