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## anonymous 5 years ago T=5((x−2)/4)+1

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1. anonymous

and solve for what?

2. anonymous

x

3. anonymous

sorry

4. anonymous

steps please.

5. anonymous

I answered that.

6. anonymous

i still dont understand it though

7. anonymous

Do you know why you can equate two sides of an equation?

8. anonymous

$x=\frac{2}{5} (3+2 T)$

9. anonymous

i know about the order of operations thats not what I need to know.

10. anonymous

i need all steps from beginning please!

11. anonymous

Robtobey how did you get your solution?

12. anonymous

there is no 10 in the equation...

13. anonymous

*facepalm*

14. anonymous

jwaddell your equation is little confusing. if solve for x. then x would equal some number with T in them.

15. anonymous

yes i know

16. anonymous

if you solve it that way then. $x=(4(\frac{T}{5})-1)+2$

17. anonymous

WOW the T is throwing me off

18. anonymous

first, distribute 5 to (x-2)/2 sop, we get (5x-10)/4 + 1=0, if T=0 then, the LCD is 4, so it will become (5x-10+4)/4=0 5x-6=0 5x=6 x=1.2

19. anonymous

if T=0 then x=1.1999999999

20. anonymous

or, if the value of T is not given, then, x=(4T+6)/5

21. anonymous

Pat yours makes sense thanks!

22. anonymous

you are welcome.

23. anonymous

thanks for the medal.

24. anonymous

no prob you wanna help me with one more?

25. anonymous

sure.

26. anonymous

$A= (3m+2)/(m-1)$

27. anonymous

solve for m

28. anonymous

m=(A(m-1)-2)/3

29. anonymous

that is not right pat. since the other m is there also.

30. anonymous

yeah, i had a mistake, i did not see it. thanks

31. anonymous

m=(A+2)/(A-3) what did you get?

32. anonymous

can u show me the steps too please

33. anonymous

m=(-2-A)/3-A

34. anonymous

(3m+2)/(m-1)=A, then cross multiply, you will get 3m+2=Am-A 3m-Am=-2-A m(3-A)=-2-A m=(-2-A)/(3-A)

35. anonymous

would't it be Am-3m=2-A???

36. anonymous

or actually Am-3m-2+A

37. anonymous

jwaddell06, Do you still want to see how the first problem was solved, now that the dust has settled?

38. anonymous

$T=\frac{5 (x-2)}{4}+1$$T-1=\frac{5 (x-2)}{4}$$4(T-1)=5 (x-2)$$\frac{4(T-1)}{5}=(x-2)$$\frac{4(T-1)}{5}+2=x$Simplify the left side to obtain:$\frac{2}{5} (2 T+3)=x$

39. anonymous

now why wouldnt you multiply the 5 into x-2

40. anonymous

The object is to isolate x on the right hand equation side. The easiest path for me was to divide by 5 leaving x - 2. When +2 is added to each side, x is left alone.

41. anonymous

That makes sense a little but i thought whenever you were given something like 5(x-2) you were supposed to make it 5x-10 then isolate x from there.

42. anonymous

Well the final result should be OK. Give me a minute to work it out.

43. anonymous

$4(T-1)=5 (x-2)$$4(T-1)=5 x-10$$4(T-1)+10=5 x$$\frac{4(T-1)+10}{5}=x$$\frac{2}{5} (2 T+3)=x$

44. anonymous

ok i get it up to the last part how do you get 2/5(2T+3)

45. anonymous

$\frac{4(T-1)+10}{5}$Simplify the numerator$\frac{(4 T+6)}{5}$Factor the numerator$\frac{(2 (2 T+3))}{5}=x$Factor the expresssion$\frac{2}{5} (2 T+3)$ I actually use Mathematica to do the calculations and had to resolve the problem by hand to answer you follow up questions.

46. anonymous

what is mathematica??

47. anonymous

I have to break off for about 10 minutes. Will be back then to answer any other questions.

48. anonymous

i dont understand how to simplify the numerator like that. sorry its been 10 years since I did algebra if not longer.

49. anonymous

what is mathematica?? Here is an introductory video. http://www.wolfram.com/solutions/education/students/

50. anonymous

Simplification is a nicety, but not required to present a valid problem solution.

51. anonymous

You're still looking at this .-.

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