anonymous
  • anonymous
T=5((x−2)/4)+1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
and solve for what?
anonymous
  • anonymous
x
anonymous
  • anonymous
sorry

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anonymous
  • anonymous
steps please.
anonymous
  • anonymous
I answered that.
anonymous
  • anonymous
i still dont understand it though
anonymous
  • anonymous
Do you know why you can equate two sides of an equation?
anonymous
  • anonymous
\[x=\frac{2}{5} (3+2 T) \]
anonymous
  • anonymous
i know about the order of operations thats not what I need to know.
anonymous
  • anonymous
i need all steps from beginning please!
anonymous
  • anonymous
Robtobey how did you get your solution?
anonymous
  • anonymous
there is no 10 in the equation...
anonymous
  • anonymous
*facepalm*
anonymous
  • anonymous
jwaddell your equation is little confusing. if solve for x. then x would equal some number with T in them.
anonymous
  • anonymous
yes i know
anonymous
  • anonymous
if you solve it that way then. \[x=(4(\frac{T}{5})-1)+2\]
anonymous
  • anonymous
WOW the T is throwing me off
anonymous
  • anonymous
first, distribute 5 to (x-2)/2 sop, we get (5x-10)/4 + 1=0, if T=0 then, the LCD is 4, so it will become (5x-10+4)/4=0 5x-6=0 5x=6 x=1.2
anonymous
  • anonymous
if T=0 then x=1.1999999999
anonymous
  • anonymous
or, if the value of T is not given, then, x=(4T+6)/5
anonymous
  • anonymous
Pat yours makes sense thanks!
anonymous
  • anonymous
you are welcome.
anonymous
  • anonymous
thanks for the medal.
anonymous
  • anonymous
no prob you wanna help me with one more?
anonymous
  • anonymous
sure.
anonymous
  • anonymous
\[A= (3m+2)/(m-1)\]
anonymous
  • anonymous
solve for m
anonymous
  • anonymous
m=(A(m-1)-2)/3
anonymous
  • anonymous
that is not right pat. since the other m is there also.
anonymous
  • anonymous
yeah, i had a mistake, i did not see it. thanks
anonymous
  • anonymous
m=(A+2)/(A-3) what did you get?
anonymous
  • anonymous
can u show me the steps too please
anonymous
  • anonymous
m=(-2-A)/3-A
anonymous
  • anonymous
(3m+2)/(m-1)=A, then cross multiply, you will get 3m+2=Am-A 3m-Am=-2-A m(3-A)=-2-A m=(-2-A)/(3-A)
anonymous
  • anonymous
would't it be Am-3m=2-A???
anonymous
  • anonymous
or actually Am-3m-2+A
anonymous
  • anonymous
jwaddell06, Do you still want to see how the first problem was solved, now that the dust has settled?
anonymous
  • anonymous
\[T=\frac{5 (x-2)}{4}+1 \]\[T-1=\frac{5 (x-2)}{4} \]\[4(T-1)=5 (x-2)\]\[\frac{4(T-1)}{5}=(x-2)\]\[\frac{4(T-1)}{5}+2=x \]Simplify the left side to obtain:\[\frac{2}{5} (2 T+3)=x \]
anonymous
  • anonymous
now why wouldnt you multiply the 5 into x-2
anonymous
  • anonymous
The object is to isolate x on the right hand equation side. The easiest path for me was to divide by 5 leaving x - 2. When +2 is added to each side, x is left alone.
anonymous
  • anonymous
That makes sense a little but i thought whenever you were given something like 5(x-2) you were supposed to make it 5x-10 then isolate x from there.
anonymous
  • anonymous
Well the final result should be OK. Give me a minute to work it out.
anonymous
  • anonymous
\[4(T-1)=5 (x-2) \]\[4(T-1)=5 x-10 \]\[4(T-1)+10=5 x \]\[\frac{4(T-1)+10}{5}=x \]\[\frac{2}{5} (2 T+3)=x \]
anonymous
  • anonymous
ok i get it up to the last part how do you get 2/5(2T+3)
anonymous
  • anonymous
\[\frac{4(T-1)+10}{5} \]Simplify the numerator\[\frac{(4 T+6)}{5}\]Factor the numerator\[\frac{(2 (2 T+3))}{5}=x \]Factor the expresssion\[\frac{2}{5} (2 T+3) \] I actually use Mathematica to do the calculations and had to resolve the problem by hand to answer you follow up questions.
anonymous
  • anonymous
what is mathematica??
anonymous
  • anonymous
I have to break off for about 10 minutes. Will be back then to answer any other questions.
anonymous
  • anonymous
i dont understand how to simplify the numerator like that. sorry its been 10 years since I did algebra if not longer.
anonymous
  • anonymous
what is mathematica?? Here is an introductory video. http://www.wolfram.com/solutions/education/students/
anonymous
  • anonymous
Simplification is a nicety, but not required to present a valid problem solution.
anonymous
  • anonymous
You're still looking at this .-.

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