anonymous
  • anonymous
Evaluate the following limits: lim x-> 0 (x-1)/ (3sin(x)- cos (x))
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
in this case you can just plug x=0 into the function
anonymous
  • anonymous
the limit is -1/-1=1
anonymous
  • anonymous
so you should always substitute to see if its indeterminate form first? ok...thanks so much lol

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anonymous
  • anonymous
if it's indeterminate we need to use some other tools to evaluate the limit.
anonymous
  • anonymous
the reason we were able to plug in here is the function in the numerator and denominator are continuous, and we are not dividing by 0
anonymous
  • anonymous
can you explain how you know its continuous by just looking at it or did you figure it out some other way
anonymous
  • anonymous
can you explain how you know its continuous by just looking at it or did you figure it out some other way

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