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anonymous
 5 years ago
Find an equation of the plane.
The plane passes through the points (5, 3, 1) and (5, 1, 5) and is perpendicular to the plane
8x + 9y + 2z = 11.
anonymous
 5 years ago
Find an equation of the plane. The plane passes through the points (5, 3, 1) and (5, 1, 5) and is perpendicular to the plane 8x + 9y + 2z = 11.

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I found the vector of two points, crossed points w/ a,b,c from eq of plane. then I plugged into eq. of plane formula. what did I do wrong?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Check your answer by taking dot product of two perpendicular vectors.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I see a mistake in my calculation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What is wrong in my method?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(5,3,1) (5,1,5) > <0,2,6> <0,2,6>X<8,9,2>=<50,48,16> <50,48,16>.<8,9,2> = 0 <50,48,16>=<25,24,8> 25(x5)^224(y3)^2+8(z1)=0 25x12524y72+8z8=0 25x24y+8z=205

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What does your answer say in book, apparently you are checking it?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0chag (sorry to interrupt) did you ask about the calculus dream problem or was that someone else

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There is another method, I don't know if this is valid <a,b,c>dot V=0. it gives you 25x27y+2z=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You asked what is wrong with your method. The mistake is when you did the equation formula you squared x and y; you shouldn't have squared it 25x24y+8z=? Plug in (5,3,1) and you get 25x24y+8z=61
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