## anonymous 5 years ago Which equation is the perpendicular bisector of the line segment with endpoints (-2, 4) and (6, 8)

1. Owlfred

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2. anonymous

first you need the slope of this line which is $m=\frac{8-4}{6-(-2)}=\frac{4}{8}=\frac{1}{2}$

3. anonymous

since $m=\frac{1}{2}$ this means the perpendicular line has slope $m=-2$ the negative reciprocal now we need to find a point on that line

4. anonymous

the midpoint between (-2,4) and (6,8) is $(\frac{-2+6}{2},\frac{4+8}{2})=(2,6)$

5. anonymous

use point slope formula to get $y-6=-2(x-2)$ $y-6=-2x+4$ $y=-2x+10$