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anonymous
 5 years ago
solve
w^44w²2=0
cant figure out what i am doing wrong
u=w²
u²4u2=0
u=2(sqrt)6 or u=2+(sqrt)6
w²=2(sqrt)6 or w²=2+(sqrt)6
w=(sqrt)2+(sqrt)6, (sqrt)2+(sqrt)6
tell me what i am doing wrong and how to fix it plz
anonymous
 5 years ago
solve w^44w²2=0 cant figure out what i am doing wrong u=w² u²4u2=0 u=2(sqrt)6 or u=2+(sqrt)6 w²=2(sqrt)6 or w²=2+(sqrt)6 w=(sqrt)2+(sqrt)6, (sqrt)2+(sqrt)6 tell me what i am doing wrong and how to fix it plz

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nothing wrong at the beginning. you get \[w^2=2+\sqrt{6}\] \[w=\pm \sqrt{2+\sqrt{6}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is your final calculation that is off. you only need to take the square root of your solution for \[w^2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now \[2\sqrt{6}<0\] so if you are working only with real numbers this answer gives no solution for w

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did this make sense? the only mistake you made was taking the square root of \[2+\sqrt{6}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you have to put the square root sign over the whole expression

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0w=sqrt [ 2+sqrt [6] ]
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