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anonymous

  • 5 years ago

solve w^4-4w²-2=0 cant figure out what i am doing wrong u=w² u²-4u-2=0 u=2-(sqrt)6 or u=2+(sqrt)6 w²=2-(sqrt)6 or w²=2+(sqrt)6 w=(sqrt)2+(sqrt)6, -(sqrt)2+(sqrt)6 tell me what i am doing wrong and how to fix it plz

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  1. anonymous
    • 5 years ago
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    nothing wrong at the beginning. you get \[w^2=2+\sqrt{6}\] \[w=\pm \sqrt{2+\sqrt{6}}\]

  2. anonymous
    • 5 years ago
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    it is your final calculation that is off. you only need to take the square root of your solution for \[w^2\]

  3. anonymous
    • 5 years ago
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    now \[2-\sqrt{6}<0\] so if you are working only with real numbers this answer gives no solution for w

  4. anonymous
    • 5 years ago
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    did this make sense? the only mistake you made was taking the square root of \[2+\sqrt{6}\]

  5. anonymous
    • 5 years ago
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    shes an idiot

  6. anonymous
    • 5 years ago
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    thats whats off

  7. anonymous
    • 5 years ago
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    you have to put the square root sign over the whole expression

  8. anonymous
    • 5 years ago
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    w=sqrt [ 2+sqrt [6] ]

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