anonymous
  • anonymous
solve w^4-4w²-2=0 cant figure out what i am doing wrong u=w² u²-4u-2=0 u=2-(sqrt)6 or u=2+(sqrt)6 w²=2-(sqrt)6 or w²=2+(sqrt)6 w=(sqrt)2+(sqrt)6, -(sqrt)2+(sqrt)6 tell me what i am doing wrong and how to fix it plz
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
nothing wrong at the beginning. you get \[w^2=2+\sqrt{6}\] \[w=\pm \sqrt{2+\sqrt{6}}\]
anonymous
  • anonymous
it is your final calculation that is off. you only need to take the square root of your solution for \[w^2\]
anonymous
  • anonymous
now \[2-\sqrt{6}<0\] so if you are working only with real numbers this answer gives no solution for w

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anonymous
  • anonymous
did this make sense? the only mistake you made was taking the square root of \[2+\sqrt{6}\]
anonymous
  • anonymous
shes an idiot
anonymous
  • anonymous
thats whats off
anonymous
  • anonymous
you have to put the square root sign over the whole expression
anonymous
  • anonymous
w=sqrt [ 2+sqrt [6] ]

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