anonymous
  • anonymous
one number is five times another number. a third number is twelve more than the larger of the first two. the sum of the numbers 89. find the numbers. some one please answer this!!!!!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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mattfeury
  • mattfeury
You don't need to post this multiple times. Just once please, and someone will help here.
anonymous
  • anonymous
someone please answer it then
anonymous
  • anonymous
lucas, are you figuring it out??/

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anonymous
  • anonymous
Yes.
anonymous
  • anonymous
good lucas, make it faster i need this stacked :) :P
anonymous
  • anonymous
5A= B C = 12B A+B+C= 89 A+5A+60A= 89 66A=89 Answers: A = 1.35 B = 6.75 C = 81
anonymous
  • anonymous
gw 2011, a lil' faster!!!!!
gw2011
  • gw2011
Let x=the first number Then 5x=the second number And 5x+12=the third number Now adding the above you get: x+5x+5x+12=89 11x+12=89 11x=77 x=7 This is the first number 5x=(5)(7)=35 This is the second number 5x+12=35+12+47 This is the third number
gw2011
  • gw2011
The third number should be written as 5x+12=35+12=47. The plus 47 should be equals 47.
anonymous
  • anonymous
gw2011 is right, I read the problem wrong and calculated the third number being 12 times rather than 12 more.
anonymous
  • anonymous
kk thanks lucas and gw2011 love you lots

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