## anonymous 5 years ago i have a couple of math problems to solve anyone care to help me one on one plz...i really appreciate it

1. anonymous

2. anonymous

$h(x)=\sqrt{4x+8}$ 4x+8≥0 4x≥-8 x≥-2 D:(x I x≥-2, x E R)

3. anonymous

I REALLY THANK U FOR HELPING ME OUT

4. anonymous

you're welcome

5. anonymous

I GET CONFUSED BECAUSE I HAVENT DONE THIS MATH IN A LONG WHILE..CAN U FINISH HELPING ME PLZ...ONLY IF U CAN

6. anonymous

ok number 11 a) f(x) - g(x) + h(x) just plug the functions f(x), g(x), and h(x) you'll get the result = -2x^2 + 27x -4

7. anonymous

b) g(x)/h(x) again, just plug g(x) and h(x) (10x^2 - 15x)/5x = 2x-3

8. anonymous

im confused on number 11a

9. anonymous

i inserted f g h

10. anonymous

but i got: $f(23x-4) - G(85) + h(5X)$

11. anonymous

f(x) - g(x) + h(x) = (8x^2 +7x-4) - (10x^2 -15x) + (5x) 8x^2 +7x-4 - 10x^2 + 15x + 5x

12. anonymous

where did you get that? you just need to substitute f(x) with 8x^2 +7x-4 substitute g(x) with 10x^2 -15x and substitute h(x) with 5x

13. anonymous

i got confused ...now i see it...ughhhhh *sign*

14. anonymous

15. anonymous

number 12 is about function composition g(f(3)) first, find f(3) f(x) = 8x^2 +7x-4 so f(3) = 8(3)^2 + 7(3) -4 f(3) = 8(9) + 21 -4 f(3) = 72+21-4 f(3) = 89 therefore g(f(3)) = g(89) g(x) = 10x^2 -15x g(89) = 10(89)^2 - 15(89)

16. anonymous

number 12 is confusing "O

17. anonymous

13) because M is the midpoint, AM=MB 2x^2 - 10x + 15 = x^2 - 2x + 3 x^2 - 8x + 12 = 0 (x-6)(x-2) x = 6 or x=2

18. anonymous

this is an article from wikipedia , related to number 12 http://en.wikipedia.org/wiki/Function_composition

19. anonymous

thanks

20. anonymous

21. anonymous

14) AC is an angle bisector, therefore angle BAD = angle CAD x^2 = 5x + 24 x^2 - 5x - 24=0 (x-8)(x+3) x=8 or x=-3

22. anonymous

15) BAD is a right angle 4x+8+7x+5 = 90 degree 11x + 13 = 90 11x = 77 x=7

23. anonymous

16) 8x+12 + 2x+8 = 180 degree 10x + 20 = 180 10x = 160 x= 16

24. anonymous

25. anonymous

17) x^2 = 6x-8

26. anonymous

for number 12 how did we get 8 if the problem is f(x) = 3x -4 and g(x) = x to the 2nd -5 you dont have to redo the problem just need to know how 8 got there

27. anonymous

oh, sorry, i did it wrong, i didnt see the f(x) and g(x) in number 11 and 12 are different, i'll do it again

28. anonymous

ok thanks

29. anonymous

f(x) = 3x -4 and g(x) = x^2 - 5 f(3) = 3(3) - 4 = 9-4 = 5 because f(3) = 5, g(f(3)) = g(5) g(5) = (5)^2 - 5 = 25-5 = 20

30. anonymous

thank you very much for correcting it ")

31. anonymous

32. anonymous

19, because it's an iscoceles triangle, angle C must be the same as angle A. a triangle has an angle of 180 degree, so : A + B + C = 180 degree 2x^2 + x^2 + 2x^2 = 180

33. anonymous

34. anonymous

god ur good at this

35. anonymous

can i borrow ur brains for my finals...lol ")

36. anonymous

this is for number 20

37. anonymous

lol, not really good, actually, this is kinda like SAT problems

38. anonymous

damn then i am dumb "(

39. anonymous

40. anonymous

you just need to keep practicing, you'll be good at this. sorry i can't continue this, i gotta go. bye

41. anonymous

ok thank u very much for all ur help