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anonymous
 5 years ago
i have a couple of math problems to solve anyone care to help me one on one plz...i really appreciate it
anonymous
 5 years ago
i have a couple of math problems to solve anyone care to help me one on one plz...i really appreciate it

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[h(x)=\sqrt{4x+8}\] 4x+8≥0 4x≥8 x≥2 D:(x I x≥2, x E R)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I REALLY THANK U FOR HELPING ME OUT

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I GET CONFUSED BECAUSE I HAVENT DONE THIS MATH IN A LONG WHILE..CAN U FINISH HELPING ME PLZ...ONLY IF U CAN

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok number 11 a) f(x)  g(x) + h(x) just plug the functions f(x), g(x), and h(x) you'll get the result = 2x^2 + 27x 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0b) g(x)/h(x) again, just plug g(x) and h(x) (10x^2  15x)/5x = 2x3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im confused on number 11a

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but i got: \[f(23x4)  G(85) + h(5X)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(x)  g(x) + h(x) = (8x^2 +7x4)  (10x^2 15x) + (5x) 8x^2 +7x4  10x^2 + 15x + 5x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0where did you get that? you just need to substitute f(x) with 8x^2 +7x4 substitute g(x) with 10x^2 15x and substitute h(x) with 5x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got confused ...now i see it...ughhhhh *sign*

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0number 12 is about function composition g(f(3)) first, find f(3) f(x) = 8x^2 +7x4 so f(3) = 8(3)^2 + 7(3) 4 f(3) = 8(9) + 21 4 f(3) = 72+214 f(3) = 89 therefore g(f(3)) = g(89) g(x) = 10x^2 15x g(89) = 10(89)^2  15(89)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0number 12 is confusing "O

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.013) because M is the midpoint, AM=MB 2x^2  10x + 15 = x^2  2x + 3 x^2  8x + 12 = 0 (x6)(x2) x = 6 or x=2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is an article from wikipedia , related to number 12 http://en.wikipedia.org/wiki/Function_composition

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.014) AC is an angle bisector, therefore angle BAD = angle CAD x^2 = 5x + 24 x^2  5x  24=0 (x8)(x+3) x=8 or x=3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.015) BAD is a right angle 4x+8+7x+5 = 90 degree 11x + 13 = 90 11x = 77 x=7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.016) 8x+12 + 2x+8 = 180 degree 10x + 20 = 180 10x = 160 x= 16

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for number 12 how did we get 8 if the problem is f(x) = 3x 4 and g(x) = x to the 2nd 5 you dont have to redo the problem just need to know how 8 got there

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh, sorry, i did it wrong, i didnt see the f(x) and g(x) in number 11 and 12 are different, i'll do it again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(x) = 3x 4 and g(x) = x^2  5 f(3) = 3(3)  4 = 94 = 5 because f(3) = 5, g(f(3)) = g(5) g(5) = (5)^2  5 = 255 = 20

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you very much for correcting it ")

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.019, because it's an iscoceles triangle, angle C must be the same as angle A. a triangle has an angle of 180 degree, so : A + B + C = 180 degree 2x^2 + x^2 + 2x^2 = 180

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can i borrow ur brains for my finals...lol ")

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is for number 20

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, not really good, actually, this is kinda like SAT problems

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0damn then i am dumb "(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you just need to keep practicing, you'll be good at this. sorry i can't continue this, i gotta go. bye

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thank u very much for all ur help
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