- anonymous

i have a couple of math problems to solve anyone care to help me one on one plz...i really appreciate it

- jamiebookeater

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- anonymous

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- anonymous

\[h(x)=\sqrt{4x+8}\]
4x+8≥0
4x≥-8
x≥-2
D:(x I x≥-2, x E R)

- anonymous

I REALLY THANK U FOR HELPING ME OUT

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- anonymous

you're welcome

- anonymous

I GET CONFUSED BECAUSE I HAVENT DONE THIS MATH IN A LONG WHILE..CAN U FINISH HELPING ME PLZ...ONLY IF U CAN

- anonymous

ok number 11
a) f(x) - g(x) + h(x)
just plug the functions f(x), g(x), and h(x)
you'll get the result = -2x^2 + 27x -4

- anonymous

b) g(x)/h(x)
again, just plug g(x) and h(x)
(10x^2 - 15x)/5x = 2x-3

- anonymous

im confused on number 11a

- anonymous

i inserted f g h

- anonymous

but i got: \[f(23x-4) - G(85) + h(5X)\]

- anonymous

f(x) - g(x) + h(x) =
(8x^2 +7x-4) - (10x^2 -15x) + (5x)
8x^2 +7x-4 - 10x^2 + 15x + 5x

- anonymous

where did you get that?
you just need to substitute f(x) with 8x^2 +7x-4
substitute g(x) with 10x^2 -15x
and substitute h(x) with 5x

- anonymous

i got confused ...now i see it...ughhhhh *sign*

- anonymous

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- anonymous

number 12 is about function composition
g(f(3))
first, find f(3)
f(x) = 8x^2 +7x-4 so
f(3) = 8(3)^2 + 7(3) -4
f(3) = 8(9) + 21 -4
f(3) = 72+21-4
f(3) = 89
therefore g(f(3)) = g(89)
g(x) = 10x^2 -15x
g(89) = 10(89)^2 - 15(89)

- anonymous

number 12 is confusing "O

- anonymous

13) because M is the midpoint, AM=MB
2x^2 - 10x + 15 = x^2 - 2x + 3
x^2 - 8x + 12 = 0
(x-6)(x-2)
x = 6 or x=2

- anonymous

this is an article from wikipedia , related to number 12
http://en.wikipedia.org/wiki/Function_composition

- anonymous

thanks

- anonymous

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- anonymous

14) AC is an angle bisector, therefore
angle BAD = angle CAD
x^2 = 5x + 24
x^2 - 5x - 24=0
(x-8)(x+3)
x=8 or x=-3

- anonymous

15) BAD is a right angle
4x+8+7x+5 = 90 degree
11x + 13 = 90
11x = 77
x=7

- anonymous

16) 8x+12 + 2x+8 = 180 degree
10x + 20 = 180
10x = 160
x= 16

- anonymous

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- anonymous

17) x^2 = 6x-8

- anonymous

for number 12 how did we get 8 if the problem is f(x) = 3x -4 and g(x) = x to the 2nd -5 you dont have to redo the problem just need to know how 8 got there

- anonymous

oh, sorry, i did it wrong, i didnt see the f(x) and g(x) in number 11 and 12 are different, i'll do it again

- anonymous

ok thanks

- anonymous

f(x) = 3x -4 and g(x) = x^2 - 5
f(3) = 3(3) - 4 = 9-4 = 5
because f(3) = 5, g(f(3)) = g(5)
g(5) = (5)^2 - 5 = 25-5 = 20

- anonymous

thank you very much for correcting it ")

- anonymous

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- anonymous

19, because it's an iscoceles triangle, angle C must be the same as angle A.
a triangle has an angle of 180 degree, so :
A + B + C = 180 degree
2x^2 + x^2 + 2x^2 = 180

- anonymous

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- anonymous

god ur good at this

- anonymous

can i borrow ur brains for my finals...lol ")

- anonymous

this is for number 20

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- anonymous

lol, not really good, actually, this is kinda like SAT problems

- anonymous

damn then i am dumb "(

- anonymous

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- anonymous

you just need to keep practicing, you'll be good at this.
sorry i can't continue this, i gotta go. bye

- anonymous

ok thank u very much for all ur help

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