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anonymous

  • 5 years ago

What is the simplified form of the reciprocal of negative squaroot 48?

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  1. anonymous
    • 5 years ago
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    \[-\frac{1}{\sqrt{48}}\] \[-\frac{1}{\sqrt{16\times 3}}\] \[-\frac{1}{4\sqrt{3}}\] \[-\frac{1}{4\sqrt{3}}\times \frac{\sqrt{3}}{\sqrt{3}}\]

  2. anonymous
    • 5 years ago
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    \[-\frac{\sqrt{3}}{12}\]

  3. anonymous
    • 5 years ago
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    ur smart... i feel so dumb

  4. anonymous
    • 5 years ago
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    you get used to doing these. multiply top and bottom by radical to get it out of denominator

  5. anonymous
    • 5 years ago
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    Can you help me with this problem.... Simplify: squareroot of 0.6

  6. anonymous
    • 5 years ago
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    always look for a perfect square inside radial. \[\sqrt{50}=\sqrt{25\times 2}=5\sqrt{2}\]

  7. anonymous
    • 5 years ago
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    yes.

  8. anonymous
    • 5 years ago
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    \[\sqrt{.6}=\sqrt{\frac{6}{10}}=\sqrt{\frac{3}{5}}\]

  9. anonymous
    • 5 years ago
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    now rationalize the denominator \[\frac{\sqrt{3}}{\sqrt{5}}\times\frac{\sqrt{5}}{\sqrt{5}}=\frac{\sqrt{15}}{5}\]\]

  10. anonymous
    • 5 years ago
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    do you know how to solve this one? If 3x + 4y = 7 and 2x-3y=67 then which of the following is the value of xy?

  11. anonymous
    • 5 years ago
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    sure you have to solve the system and then multiply

  12. anonymous
    • 5 years ago
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    can you solve this system?

  13. anonymous
    • 5 years ago
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    wait what do you mean by solving the system and multiplying

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