Last one for the night and my homework is done. Woohoo. :)
When P dollars is invested at interest rate i, compounded annually, for t years, the investment grows to A dollars, where A=P(1 + i)^t. Find the interest rate if $2490 grows to $3630 in 2 years. Round your answer to the nearest hundredth of a percent.

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3630/2490 = x^2 +2x+1

go from there

\[2490(1+i)^2=3630\]
\[(1+i)^2=\frac{3630}{2490}=1.4578\]

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