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anonymous
 5 years ago
i need to prove the chain rule for [f(g(h(x)))]=f'(g(h(x))g'(h(x))h'(x) using the limit definition of the derivative
anonymous
 5 years ago
i need to prove the chain rule for [f(g(h(x)))]=f'(g(h(x))g'(h(x))h'(x) using the limit definition of the derivative

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Owlfred
 5 years ago
Best ResponseYou've already chosen the best response.0Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i don't believe you. this is amazingly hard.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in fact if you look in your text i am willing to bet they do not even prove the chain rule. at some point they will say "it is reasonable to believe that ..." and not actually prove it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what text are you using?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no its proven in my text but i do not understand how to add the third funtion into the given proof and im using calculus early transcendentals by jon rogawski

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0very nice. not a proof though

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what if h is a constant function? that is the problem with all these proofs

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait whats very nice but not a proof

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0brittT myinanaya has it, use that one

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use what myinanaya wrote. it is good

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is very helpful!

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0satellitle like so you mean if h(x)=5 then no matter what change x happens h will always be the same so we have lim deltax>0 (55)/h=0/h=0

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0oh by the way that is suppose to say deltax>0 not h>0 o nthat attachment

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well my problem also states that they are all differntiable and if it was a constant then it would not work and yeah i figured thats what you ment thank you

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0oh yeah f(g(0)) i don't think will work i understand

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the problem with all these proof is they ignore what can happen if the "inside function" is a constant. but ignore me because you (brittT) clearly don't have to worry about it. forget i mentioned it. but a rigorous proof of the chain rule is a pain

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0see serge lang calculus if you want a real proof. that is why i asked what text you were using. use myinanaya's proof.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0or i mean it doesnt have to be zero but a constant yeah

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0the first one is my proof yeah! lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i will be willing to bet cash that it is the proof in the text brittT is using

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0better explanation of what is wrong http://math.rice.edu/~cjd/chainrule.pdf

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the flaw is that if \[g(x)=c\] a constant, then the denominator is identically 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am using what myininaya posted
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