Find equation of the plane that contains following vectors
is it 9x+2y-5z? I mean I just need to make the cross product? as there are no point to use to substitute to general formula.
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The cross product will give you a vector which is perpendicular to the plane. Since you know that this vector is perpendicular to your plane, the dot product of it and any point in the plane will be 0. Therefore your plane will be all the points which are solutions to the equation 9x + 2y - 5z = 0.
this quation is not complete, no particular solotion for this problem. However, the general solution is 9x+2y-5z=d, where d is any costant.
Jack, I disagree. Since the plane contains those vectors (not parallel to them) the plane goes through the origin. Therefore the constant d in your example must be 0.