anonymous
  • anonymous
Can someone show the steps to solve this other equation? 2(3t+1)-5=t-(t+2)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
just multiply then solve for t 2(3t+1) will give 6t+2 , and t-(t+2) will give t-t-2 = -2 equalize them 6t+2=-2 6t=-4 t=-4/6
anonymous
  • anonymous
I understood the 2(3t+1) part but i dont get the rest.
anonymous
  • anonymous
try to read again, t-(t+2) will give t-t-2 = -2 now substitute them in the original formula 6t+2 (from 2(3t+1)) = -2 (from t-(t+2)) 6t+2=-2 6t=-4 t=-4/6

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anonymous
  • anonymous
6t+2-5=t-t-2 6t-3=-2 6t=3-2 6t=1 t=1/6
anonymous
  • anonymous
man I forgot the minus 5 ><.. 6t+2-5=-2 6t-3=-2 6t=-2+3 6t=1 t=1/6
anonymous
  • anonymous
6t+2=8t then -5 makes it 3t? How'd you get -2?
anonymous
  • anonymous
i got -2 by distributing the negative there to (t+2) which gave me -t-2
anonymous
  • anonymous
pat
anonymous
  • anonymous
yes?

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