## anonymous 5 years ago need help with math problems

1. anonymous

2. anonymous

thank you for helping me i will give u lots of metals :)

3. anonymous

Is it both questions or just the second one?

4. anonymous

2nd one

5. anonymous

OK I will oput some explanations down to help you understand.

6. anonymous

nancy is helping me thanks gianfranco

7. anonymous

i think she is

8. anonymous

nancy i need help with both..i got confused i thought this was the other paper

9. anonymous

Get back to me if you need to then )

10. anonymous

thank u

11. anonymous

frist find cost B CosB =3/7 B = 64.6 degree angle A=180-(90+64.6)=25.4 degree tan B=X/3 X=3tan64.6 X=6,317 tan $\tan A=\frac{3}{6,137}$ A =26 degree I don't know u need solve for angle or not

12. anonymous

no that is good enough as long as i know the basic

13. anonymous

R u sure?

14. anonymous

let me done onr more

15. anonymous

ok thank u

16. anonymous

24) BC=1/2 BA BC=12:2= 6 $AC=6\sqrt{3}$$Sin. B =\frac{6\sqrt{3}}{12}=$$Tan. B =\frac{6\sqrt{3}}{6}$ I think u can use caculator so.ve very easy

17. anonymous

thank u nancy u been a great help

18. anonymous

good cluck your home work bye

19. anonymous

bye

20. anonymous

From the photo7.jpg:$\text{AC}=10 \text{Cot}[50\text{Degree}]= 8.391$$\text{AB}=10 \text{Csc}[50\text{Degree}]= 13.0541$To check the solutions:$\sqrt{\text{AC}^2+10^2}= 13.0541$Note: Mathematica was used for the calculations. 50Degree is converted to the equivalent radian angle measure or 50/180 * pi. For example:$10 \text{Csc}\left[\pi \left(\frac{50}{180}\right)\right]= 13.0541$