anonymous
  • anonymous
need help with math problems
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
thank you for helping me i will give u lots of metals :)
anonymous
  • anonymous
Is it both questions or just the second one?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
2nd one
anonymous
  • anonymous
OK I will oput some explanations down to help you understand.
anonymous
  • anonymous
nancy is helping me thanks gianfranco
anonymous
  • anonymous
i think she is
anonymous
  • anonymous
nancy i need help with both..i got confused i thought this was the other paper
anonymous
  • anonymous
Get back to me if you need to then )
anonymous
  • anonymous
thank u
anonymous
  • anonymous
frist find cost B CosB =3/7 B = 64.6 degree angle A=180-(90+64.6)=25.4 degree tan B=X/3 X=3tan64.6 X=6,317 tan \[\tan A=\frac{3}{6,137}\] A =26 degree I don't know u need solve for angle or not
anonymous
  • anonymous
no that is good enough as long as i know the basic
anonymous
  • anonymous
R u sure?
anonymous
  • anonymous
let me done onr more
anonymous
  • anonymous
ok thank u
anonymous
  • anonymous
24) BC=1/2 BA BC=12:2= 6 \[AC=6\sqrt{3}\]\[Sin. B =\frac{6\sqrt{3}}{12}=\]\[Tan. B =\frac{6\sqrt{3}}{6}\] I think u can use caculator so.ve very easy
anonymous
  • anonymous
thank u nancy u been a great help
anonymous
  • anonymous
good cluck your home work bye
anonymous
  • anonymous
bye
anonymous
  • anonymous
From the photo7.jpg:\[\text{AC}=10 \text{Cot}[50\text{Degree}]= 8.391 \]\[\text{AB}=10 \text{Csc}[50\text{Degree}]= 13.0541 \]To check the solutions:\[\sqrt{\text{AC}^2+10^2}= 13.0541 \]Note: Mathematica was used for the calculations. 50Degree is converted to the equivalent radian angle measure or 50/180 * pi. For example:\[10 \text{Csc}\left[\pi \left(\frac{50}{180}\right)\right]= 13.0541 \]

Looking for something else?

Not the answer you are looking for? Search for more explanations.