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anonymous

  • 5 years ago

need help with math problems

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  1. anonymous
    • 5 years ago
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  2. anonymous
    • 5 years ago
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    thank you for helping me i will give u lots of metals :)

  3. anonymous
    • 5 years ago
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    Is it both questions or just the second one?

  4. anonymous
    • 5 years ago
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    2nd one

  5. anonymous
    • 5 years ago
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    OK I will oput some explanations down to help you understand.

  6. anonymous
    • 5 years ago
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    nancy is helping me thanks gianfranco

  7. anonymous
    • 5 years ago
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    i think she is

  8. anonymous
    • 5 years ago
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    nancy i need help with both..i got confused i thought this was the other paper

  9. anonymous
    • 5 years ago
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    Get back to me if you need to then )

  10. anonymous
    • 5 years ago
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    thank u

  11. anonymous
    • 5 years ago
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    frist find cost B CosB =3/7 B = 64.6 degree angle A=180-(90+64.6)=25.4 degree tan B=X/3 X=3tan64.6 X=6,317 tan \[\tan A=\frac{3}{6,137}\] A =26 degree I don't know u need solve for angle or not

  12. anonymous
    • 5 years ago
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    no that is good enough as long as i know the basic

  13. anonymous
    • 5 years ago
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    R u sure?

  14. anonymous
    • 5 years ago
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    let me done onr more

  15. anonymous
    • 5 years ago
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    ok thank u

  16. anonymous
    • 5 years ago
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    24) BC=1/2 BA BC=12:2= 6 \[AC=6\sqrt{3}\]\[Sin. B =\frac{6\sqrt{3}}{12}=\]\[Tan. B =\frac{6\sqrt{3}}{6}\] I think u can use caculator so.ve very easy

  17. anonymous
    • 5 years ago
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    thank u nancy u been a great help

  18. anonymous
    • 5 years ago
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    good cluck your home work bye

  19. anonymous
    • 5 years ago
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    bye

  20. anonymous
    • 5 years ago
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    From the photo7.jpg:\[\text{AC}=10 \text{Cot}[50\text{Degree}]= 8.391 \]\[\text{AB}=10 \text{Csc}[50\text{Degree}]= 13.0541 \]To check the solutions:\[\sqrt{\text{AC}^2+10^2}= 13.0541 \]Note: Mathematica was used for the calculations. 50Degree is converted to the equivalent radian angle measure or 50/180 * pi. For example:\[10 \text{Csc}\left[\pi \left(\frac{50}{180}\right)\right]= 13.0541 \]

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spraguer (Moderator)
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