need help with math problems

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need help with math problems

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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thank you for helping me i will give u lots of metals :)
Is it both questions or just the second one?

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2nd one
OK I will oput some explanations down to help you understand.
nancy is helping me thanks gianfranco
i think she is
nancy i need help with both..i got confused i thought this was the other paper
Get back to me if you need to then )
thank u
frist find cost B CosB =3/7 B = 64.6 degree angle A=180-(90+64.6)=25.4 degree tan B=X/3 X=3tan64.6 X=6,317 tan \[\tan A=\frac{3}{6,137}\] A =26 degree I don't know u need solve for angle or not
no that is good enough as long as i know the basic
R u sure?
let me done onr more
ok thank u
24) BC=1/2 BA BC=12:2= 6 \[AC=6\sqrt{3}\]\[Sin. B =\frac{6\sqrt{3}}{12}=\]\[Tan. B =\frac{6\sqrt{3}}{6}\] I think u can use caculator so.ve very easy
thank u nancy u been a great help
good cluck your home work bye
bye
From the photo7.jpg:\[\text{AC}=10 \text{Cot}[50\text{Degree}]= 8.391 \]\[\text{AB}=10 \text{Csc}[50\text{Degree}]= 13.0541 \]To check the solutions:\[\sqrt{\text{AC}^2+10^2}= 13.0541 \]Note: Mathematica was used for the calculations. 50Degree is converted to the equivalent radian angle measure or 50/180 * pi. For example:\[10 \text{Csc}\left[\pi \left(\frac{50}{180}\right)\right]= 13.0541 \]

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