anonymous
  • anonymous
need help with 3 more problems plz help
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
?
anonymous
  • anonymous
i have 3 more math problems to do then i am done..lol
anonymous
  • anonymous
i dont want to keep u up

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anonymous
  • anonymous
it ok I'm free
anonymous
  • anonymous
bonus #1
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anonymous
  • anonymous
i did number 25 already
anonymous
  • anonymous
ok u want do bonus question 1?
anonymous
  • anonymous
yes plz
anonymous
  • anonymous
3x^2+5x-1=0 x=(-5+-sqrt(25+4))/6 now simplify
anonymous
  • anonymous
\[\frac{-5\pm \sqrt{5^{2}-4(3\times (-1)}}{(2\times3)} =\frac{-5\pm \sqrt{25+12}}{6}\]
anonymous
  • anonymous
OK , bye
anonymous
  • anonymous
bye
anonymous
  • anonymous
i need help with 2 more problems
anonymous
  • anonymous
Which questions do you need help on?
anonymous
  • anonymous
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anonymous
  • anonymous
number 18 on this one
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anonymous
  • anonymous
Ok opposite sides of a paralleogram are equal in length so make to equations y2 = 49 so y = 7 (answer) Other equation x + 9 = 4x - 27 subtract x from each side 9 = 3x - 27 Add 27 to each side 18 = 3x divide each side by 3 x = 6 *answer()
anonymous
  • anonymous
can u show me a break down of the first one plz
anonymous
  • anonymous
The part about paralellograms?
anonymous
  • anonymous
One side of the parallelogram is y squared and the other is 49 They are equal in length so if we take the sq root of both of them y = 7
anonymous
  • anonymous
how u got the answer because i dont get it im confused
anonymous
  • anonymous
oh we are dividing
anonymous
  • anonymous
No we are finding the square root of 49 and of y squared because they are equal
anonymous
  • anonymous
wait are we doing number 18 or bonus number 2
anonymous
  • anonymous
ohh we have to solve twice
anonymous
  • anonymous
thats where i got confused
anonymous
  • anonymous
!8 but I can do bonus 2 for you if you wish
anonymous
  • anonymous
yes please
anonymous
  • anonymous
I'm on it right now
anonymous
  • anonymous
thanks a bunch

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