How do you simplify this? n^2-4/n+2 multiplied by n/3n-6

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How do you simplify this? n^2-4/n+2 multiplied by n/3n-6

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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n^2-4 can be written as =(n-2)*(n+2) so we'll have (n-2)*(n+2) ------------= n-2 (n+2)
I need to simplify the whole equation. So I would have to multipy that to n/3n-6

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oops sorry i 4got the rest of the problem
It's okay.
(n-2)*n/3n-6=(n^2-2n)/(3n-6)
Is that the whole answer? I'm looking for just one answer that is simplified. I don't know the name of this kind of math method though...
Maybe an example would help?
3n -6 = 3(n-2) \[\frac{n(n-2)}{3(n-2)} = \frac{n}{3}\]
For example, y^2/12x is in Simplest Form
the math method is just factoring and reducing by cancelling
Yes, that's it!
I don't understand how to do the problem.
break it down, look at each term and try to factor it then cancel identical terms on top and bottom
best way to learn is to practice factoring
OKay, I saw your above answer, thank you! I think i can figure it out myself now

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