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anonymous

  • 5 years ago

How do you simplify this? n^2-4/n+2 multiplied by n/3n-6

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  1. Owlfred
    • 5 years ago
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    Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

  2. angela210793
    • 5 years ago
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    n^2-4 can be written as =(n-2)*(n+2) so we'll have (n-2)*(n+2) ------------= n-2 (n+2)

  3. anonymous
    • 5 years ago
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    I need to simplify the whole equation. So I would have to multipy that to n/3n-6

  4. angela210793
    • 5 years ago
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    oops sorry i 4got the rest of the problem

  5. anonymous
    • 5 years ago
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    It's okay.

  6. angela210793
    • 5 years ago
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    (n-2)*n/3n-6=(n^2-2n)/(3n-6)

  7. anonymous
    • 5 years ago
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    Is that the whole answer? I'm looking for just one answer that is simplified. I don't know the name of this kind of math method though...

  8. anonymous
    • 5 years ago
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    Maybe an example would help?

  9. dumbcow
    • 5 years ago
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    3n -6 = 3(n-2) \[\frac{n(n-2)}{3(n-2)} = \frac{n}{3}\]

  10. anonymous
    • 5 years ago
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    For example, y^2/12x is in Simplest Form

  11. dumbcow
    • 5 years ago
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    the math method is just factoring and reducing by cancelling

  12. anonymous
    • 5 years ago
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    Yes, that's it!

  13. anonymous
    • 5 years ago
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    I don't understand how to do the problem.

  14. dumbcow
    • 5 years ago
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    break it down, look at each term and try to factor it then cancel identical terms on top and bottom

  15. dumbcow
    • 5 years ago
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    best way to learn is to practice factoring

  16. anonymous
    • 5 years ago
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    OKay, I saw your above answer, thank you! I think i can figure it out myself now

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