factor into 2 factors with integral coefficients: x^8+98x^4+1

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

factor into 2 factors with integral coefficients: x^8+98x^4+1

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

any ideas?
wolframalpha shows: (1 + 4 x + 8 x^2 - 4 x^3 + x^4) (1 - 4 x + 8 x^2 + 4 x^3 + x^4) but how to get?
jeez

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

mad problem, :)
anyone?
\[(x ^{4}+ax ^{3}+bx ^{2}-cx +1)(x ^{4}-ax ^{3}+bx ^{2}+cx+1)\] \[= x ^{8} +(2b-a ^{2})x ^{6}+(b ^{2}+2ac+2)x ^{4} +(2b-c ^{2})x ^{2}+1\] \[2b-a ^{2} =0\] \[b^{2}+2ac+2=98\] \[2b-c^{2}=0\] solve system for a,b,c a=c=4 b=8
well dumbcow..u knew the answer before solving...:)LOL
lol true, but if you in general know the form (alternating signs so odd exponents cancel) you could solve for the coefficients
i wouldnt know if both the factors had the same set of integer coefficients:)
no but that would be the assumption since terms cancel
i think tats too much assuming...
haha ok well i tried
so here goes a medal...!:) lol
what do you mean the signs alternate?
how did you get signs to alternate?

Not the answer you are looking for?

Search for more explanations.

Ask your own question