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anonymous

  • 5 years ago

the region bounded by y=sqrt x, x = 4 , y = 0 , revolved about line y = 6 , using shell method

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  1. anonymous
    • 5 years ago
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    i got int 2pi (6-y) (0-y^2) dy , 0 to 2

  2. anonymous
    • 5 years ago
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    but im getting a negative answer

  3. anonymous
    • 5 years ago
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    maybe its int 2pi (6-y) (4-y^2) dy

  4. watchmath
    • 5 years ago
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    yes the last one is correct and we integrate from 0 to 2

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