anonymous
  • anonymous
∫ (e^x)lnx dx =?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Owlfred
  • Owlfred
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anonymous
  • anonymous
use integration by parts
anonymous
  • anonymous
Laplace20, are u sure u can get the answer by using integration by parts?????

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anonymous
  • anonymous
im never sure about anything. why dont you try it
anonymous
  • anonymous
Integration by parts impossible to solve it. 100% impossible!!!
anonymous
  • anonymous
u = ln x , dv = e^x , du = 1/x , v = e^x = ln x * e^x - integral e^x *1/x
anonymous
  • anonymous
nevermind, this cant be integrated
anonymous
  • anonymous
this is not an elementary function
anonymous
  • anonymous
algebraic, log, inverse trig, trig, exponential,
anonymous
  • anonymous
what is this a trick question?
anonymous
  • anonymous
no, this can be done using integration by parts , just you need to apply it twice
anonymous
  • anonymous
its like how you integrate e^x sin(x) or e^(x)cos(x)
anonymous
  • anonymous
contining from above, ie I (integral we want ) = ln x * e^x - integral e^x *1/x
anonymous
  • anonymous
let u=e^x , dv = (1/x) dx
anonymous
  • anonymous
so du= e^x dx , and v= ln(x)
anonymous
  • anonymous
SO I = e^x ln(x) - [ e^(x) ln(x) - integral ( e^x ln(x) dx ) ]
anonymous
  • anonymous
but that integral e^x lnx is what we started with, it was "I" so I = I huh , thats a bit strange that method didnt work :|

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