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anonymous

  • 5 years ago

shell method, revolve y=x+2, y=x^2 about the y axis

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  1. anonymous
    • 5 years ago
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    If something is revolving what kind of shape does it have?

  2. anonymous
    • 5 years ago
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    It can have a shape of a cylinder or cone so in this case you would want to set up an integral in cylindrical coordinate

  3. anonymous
    • 5 years ago
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    scratch the cylindrical coordinates. You are setting up a single integral. The boundaries of the integral are going to be the points where the functions intersect and the lowest point of y=x+ 2 then what you want to integrate is 2 * pi * r * h dx where r is the radius and h is the height.

  4. anonymous
    • 5 years ago
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    I really dislike doing single integrals for volume so if you can set up a triple integral then do it.

  5. anonymous
    • 5 years ago
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    its a single integral problem

  6. anonymous
    • 5 years ago
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    Please rewrite question word for word, make sure no info was left out.

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