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anonymous
 5 years ago
shell method, revolve y=x+2, y=x^2 about the y axis
anonymous
 5 years ago
shell method, revolve y=x+2, y=x^2 about the y axis

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If something is revolving what kind of shape does it have?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It can have a shape of a cylinder or cone so in this case you would want to set up an integral in cylindrical coordinate

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0scratch the cylindrical coordinates. You are setting up a single integral. The boundaries of the integral are going to be the points where the functions intersect and the lowest point of y=x+ 2 then what you want to integrate is 2 * pi * r * h dx where r is the radius and h is the height.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I really dislike doing single integrals for volume so if you can set up a triple integral then do it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its a single integral problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Please rewrite question word for word, make sure no info was left out.
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