find the least number between 200 and 500 which leaves a remainder of 3 in each case when divided by 8,10,12 and 30

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find the least number between 200 and 500 which leaves a remainder of 3 in each case when divided by 8,10,12 and 30

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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First find the LCM of 8,10, 12 and 30 (this is 120) Find the lowest multiple of 120 between 300 and 500 (this 360) Add 3 to this 363 That's it!
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LCM(8,10,12,30) = 120 120 < 200 120 * 2 = 240 200 < 240 < 500 -> 240+3 = 243 Solution is 243, i think.

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Other answers:

i you are right I read it as 300-500
Hey umm Why'd yu multiply by 2 aftr getting the LCM?

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