anonymous
  • anonymous
There are 10 members of a committee. One will be chosen as President, one as Vise President, one as Treasurer, and one as Secretary. In how many different ways can those offices be filled if the same person cannot serve in more than one office at the same time? a) 10!/4!6! b) 10!/4! c) 10! d) 10!/6!
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
10! / 4 !
anonymous
  • anonymous
How do you figure?
anonymous
  • anonymous
there are 10 ways to choose president. for each choice of president, there are 9 choices left for vice president, then 8 choices left for vice president ... 10*9*8*7

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anonymous
  • anonymous
oh it should be d)
anonymous
  • anonymous
nPr = n! / ( n-r)!
anonymous
  • anonymous
10*9*8*7 = 10*9*8*7 * 6! / 6!
anonymous
  • anonymous
i think maybe no.
anonymous
  • anonymous
no
anonymous
  • anonymous
oops you are right sorry
anonymous
  • anonymous
10*9*8*7
anonymous
  • anonymous
it is just that \[\frac{10!}{6!}\] is a silly way to write that
anonymous
  • anonymous
my mistake laplace is right and i am wrong

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