anonymous
  • anonymous
what are the intercepts of the equation 2x+3/2y+3z=6
Mathematics
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anonymous
  • anonymous
what are the intercepts of the equation 2x+3/2y+3z=6
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
is it (3,0,0) (0,4,0)(0,0,2)
amistre64
  • amistre64
2x+3 ------ -= 6 ; is this the equation? 2y+3z
anonymous
  • anonymous
no its a fraction

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amistre64
  • amistre64
2x +3/2y +3z = 6 this then :)
anonymous
  • anonymous
yes its a graphing equation
amistre64
  • amistre64
we need to multiply everything by y; to get rid of that bit
anonymous
  • anonymous
its gong to be 4
amistre64
  • amistre64
2xy +3/2 +3zy = 6y is the sane equation, but has no limits when y = 0
amistre64
  • amistre64
2xy +3/2 +3zy -6y = 0 y(2x +3z -6) +3/2 = 0 is another way of writing it
amistre64
  • amistre64
when x and y = 0 there is no value..... is there?
anonymous
  • anonymous
this is the answer i been got it (3,0,0) (0,4,0)(0,0,2)
amistre64
  • amistre64
is that answer correct? or is that the answer you are checking? becasue y cant = 0 in this..
amistre64
  • amistre64
(0,4,0) is good (x,0,0) is not valid, becasue y cant be 0 (0,0,z) is not valid cause y cant = 0
amistre64
  • amistre64
in other words, yo have a function that only intersects the y axis; and never touches the other 2
anonymous
  • anonymous
no, he means its a plane
anonymous
  • anonymous
not a fraction
anonymous
  • anonymous
people need to get the notation correct when asking a question , the fracts are coeffiecients of the plane
amistre64
  • amistre64
the surface is a hyperbolic cylindar
anonymous
  • anonymous
hello amistre!
amistre64
  • amistre64
oh lol
amistre64
  • amistre64
hi sat :)
anonymous
  • anonymous
did you take yesterday off?
amistre64
  • amistre64
i wish lol.... I spent the day under my front end fixing the steering parts...
anonymous
  • anonymous
i meant from "off from here"
anonymous
  • anonymous
and to the asker, yes the answers you posted in the first post are correct
amistre64
  • amistre64
it was a forced hiatus lol
anonymous
  • anonymous
oh yes. it is right. set two = 0 solve for third
amistre64
  • amistre64
2x+(3/2)y+3z=6 4x +3y +6z = 12 x=3, y=4, z=2 (3,0,0) (0,4,0) (0,0,2) would then be the intercepts yes

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