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anonymous

  • 5 years ago

what are the intercepts of the equation 2x+3/2y+3z=6

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  1. anonymous
    • 5 years ago
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    is it (3,0,0) (0,4,0)(0,0,2)

  2. amistre64
    • 5 years ago
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    2x+3 ------ -= 6 ; is this the equation? 2y+3z

  3. anonymous
    • 5 years ago
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    no its a fraction

  4. amistre64
    • 5 years ago
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    2x +3/2y +3z = 6 this then :)

  5. anonymous
    • 5 years ago
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    yes its a graphing equation

  6. amistre64
    • 5 years ago
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    we need to multiply everything by y; to get rid of that bit

  7. anonymous
    • 5 years ago
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    its gong to be 4

  8. amistre64
    • 5 years ago
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    2xy +3/2 +3zy = 6y is the sane equation, but has no limits when y = 0

  9. amistre64
    • 5 years ago
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    2xy +3/2 +3zy -6y = 0 y(2x +3z -6) +3/2 = 0 is another way of writing it

  10. amistre64
    • 5 years ago
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    when x and y = 0 there is no value..... is there?

  11. anonymous
    • 5 years ago
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    this is the answer i been got it (3,0,0) (0,4,0)(0,0,2)

  12. amistre64
    • 5 years ago
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    is that answer correct? or is that the answer you are checking? becasue y cant = 0 in this..

  13. amistre64
    • 5 years ago
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    (0,4,0) is good (x,0,0) is not valid, becasue y cant be 0 (0,0,z) is not valid cause y cant = 0

  14. amistre64
    • 5 years ago
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    in other words, yo have a function that only intersects the y axis; and never touches the other 2

  15. anonymous
    • 5 years ago
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    no, he means its a plane

  16. anonymous
    • 5 years ago
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    not a fraction

  17. anonymous
    • 5 years ago
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    people need to get the notation correct when asking a question , the fracts are coeffiecients of the plane

  18. amistre64
    • 5 years ago
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    the surface is a hyperbolic cylindar

  19. anonymous
    • 5 years ago
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    hello amistre!

  20. amistre64
    • 5 years ago
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    oh lol

  21. amistre64
    • 5 years ago
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    hi sat :)

  22. anonymous
    • 5 years ago
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    did you take yesterday off?

  23. amistre64
    • 5 years ago
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    i wish lol.... I spent the day under my front end fixing the steering parts...

  24. anonymous
    • 5 years ago
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    i meant from "off from here"

  25. anonymous
    • 5 years ago
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    and to the asker, yes the answers you posted in the first post are correct

  26. amistre64
    • 5 years ago
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    it was a forced hiatus lol

  27. anonymous
    • 5 years ago
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    oh yes. it is right. set two = 0 solve for third

  28. amistre64
    • 5 years ago
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    2x+(3/2)y+3z=6 4x +3y +6z = 12 x=3, y=4, z=2 (3,0,0) (0,4,0) (0,0,2) would then be the intercepts yes

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