anonymous
  • anonymous
Running 4/3 of his usual speed, A person improves his timing by 10 minutes. Find his usual time to cover the distance.
Mathematics
katieb
  • katieb
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amistre64
  • amistre64
s = d/t
amistre64
  • amistre64
(4/3)Ns = d/(Nt-10)
amistre64
  • amistre64
Ns = d/(Nt)

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amistre64
  • amistre64
(4/3)Ns = d/(Nt-10) Ns = d/(Nt) (4/3)d/(Nt) = d/(Nt-10)
amistre64
  • amistre64
cross multiply (4/3)d(Nt-10) = d(Nt) d(Nt(4) - 40) ----------- = d(Nt) ; /d and *3 3 Nt(4) - 40 = Nt(3) Nt(4-3) = 40
amistre64
  • amistre64
his Normalt time is 40 minutes
amistre64
  • amistre64
..... maybe lol
anonymous
  • anonymous
yes....... since time is inversely propotional to speed let his earlier time be x min so current time=3x/4 min =>x- (3x/4)= 10 =>x=40

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