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anonymous

  • 5 years ago

what is the solution to the system of equations |{ x-2y+z=10 <|{ z=6 |{ 3x-2y+2z=8 the possible answers are (0,-2,6) (0,2,6) (-1,2,6) (0,2,-6)

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  1. amistre64
    • 5 years ago
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    none of those answers make any sense with the stated problem. You can dbl check them by working the backwards; plug the values into the equations and see if they are true.

  2. anonymous
    • 5 years ago
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    k

  3. anonymous
    • 5 years ago
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    its the first one?

  4. amistre64
    • 5 years ago
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    x-2y+z=10 <-- (0,2,6) makes this false z=6 <-- (0,2,-6) makes this false 3x-2y+2z=8 <-- (0,-2,6) makes this false

  5. amistre64
    • 5 years ago
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    x-2y+z=10 ; (-1,2,6)? -1 -2(2) +6 = 10 -1 -4 +6 = 10 -5 +6 = 10 .. FALSE

  6. amistre64
    • 5 years ago
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    none of them satisfy all the equations

  7. anonymous
    • 5 years ago
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    but the first one satisfies two out of three so thats the best answer

  8. anonymous
    • 5 years ago
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    it's 0,2,6!!!!!

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