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anonymous

  • 5 years ago

You go to the doctor and he gives you 13 milligrams of radioactive dye. After 24 minutes, 4.25 milligrams of dye remain in your system. To leave the doctor's office, you must pass through a radiation detector without sounding the alarm. If the detector will sound the alarm if more than 2 milligrams of the dye are in your system, how long will your visit to the doctor take, assuming you were given the dye as soon as you arrived? Give your answer to the nearest minute. You will spend ? minutes at the doctor's office.

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  1. anonymous
    • 5 years ago
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    56 min.

  2. anonymous
    • 5 years ago
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    how? did you get it?

  3. anonymous
    • 5 years ago
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    please:)

  4. amistre64
    • 5 years ago
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    pert might help

  5. anonymous
    • 5 years ago
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    ok:)

  6. amistre64
    • 5 years ago
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    4.25 = 13(e^24t)

  7. amistre64
    • 5 years ago
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    4.25/13 = e^24t ln(4.25/13) = 24t ln(4.25/13) ---------- = t 24

  8. amistre64
    • 5 years ago
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    umm... t = rate lol

  9. amistre64
    • 5 years ago
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    we use the rate to determine when 2 is the answer

  10. amistre64
    • 5 years ago
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    2 = 13(e^rate(time))

  11. amistre64
    • 5 years ago
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    time then equals: ln(2/13) ------- = minimum time in office rate

  12. anonymous
    • 5 years ago
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    ok i see...:) hopefully i can get the next story prob right:) i have 17 of them:(

  13. amistre64
    • 5 years ago
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    http://www.wolframalpha.com/input/?i=%28ln%282%2F13%29%29%2F%28ln%284.25%2F13%29%2F24%29 says 40.18 minutes

  14. anonymous
    • 5 years ago
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    someone told me about this!:O! thanks!!

  15. anonymous
    • 5 years ago
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    the website i mean haha

  16. amistre64
    • 5 years ago
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    yeah, i just stumbled upon it one day while cleaning behind the fridge lol

  17. anonymous
    • 5 years ago
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    lol

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