anonymous
  • anonymous
When dividing rational expressions (P(x)/Q(x) divided by R(x)/S(x)), is this expression undefined when any of Q(x), R(x), or S(x) undefined?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
my guess is yes; when a peice is undefined that usually puts a damper on things
anonymous
  • anonymous
Sorry, I meant when any of those 3 are 0.
amistre64
  • amistre64
Q(x) cant be zero; and R(x) cant be zerp

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amistre64
  • amistre64
zerp is like a zero but only got its GED
anonymous
  • anonymous
S(x) can't be zero either though, because if it were, S(x)/R(x) would be 0 and that would be dividing the first part by 0, right?
amistre64
  • amistre64
You are correct
anonymous
  • anonymous
Sorry, I got screwed up, I meant it would make S(x)/R(x) undefined and thus the whole thing. Okay, I just wanted to make sure it was any of the 3.
amistre64
  • amistre64
P(x) ---- Q(x) <- cant be zero ------- R(x) <- cant be zero --- S(x) <- cant be zero
anonymous
  • anonymous
Perfect.

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