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anonymous

  • 5 years ago

When dividing rational expressions (P(x)/Q(x) divided by R(x)/S(x)), is this expression undefined when any of Q(x), R(x), or S(x) undefined?

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  1. amistre64
    • 5 years ago
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    my guess is yes; when a peice is undefined that usually puts a damper on things

  2. anonymous
    • 5 years ago
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    Sorry, I meant when any of those 3 are 0.

  3. amistre64
    • 5 years ago
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    Q(x) cant be zero; and R(x) cant be zerp

  4. amistre64
    • 5 years ago
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    zerp is like a zero but only got its GED

  5. anonymous
    • 5 years ago
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    S(x) can't be zero either though, because if it were, S(x)/R(x) would be 0 and that would be dividing the first part by 0, right?

  6. amistre64
    • 5 years ago
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    You are correct

  7. anonymous
    • 5 years ago
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    Sorry, I got screwed up, I meant it would make S(x)/R(x) undefined and thus the whole thing. Okay, I just wanted to make sure it was any of the 3.

  8. amistre64
    • 5 years ago
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    P(x) ---- Q(x) <- cant be zero ------- R(x) <- cant be zero --- S(x) <- cant be zero

  9. anonymous
    • 5 years ago
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    Perfect.

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