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anonymous
 5 years ago
When dividing rational expressions (P(x)/Q(x) divided by R(x)/S(x)), is this expression undefined when any of Q(x), R(x), or S(x) undefined?
anonymous
 5 years ago
When dividing rational expressions (P(x)/Q(x) divided by R(x)/S(x)), is this expression undefined when any of Q(x), R(x), or S(x) undefined?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1my guess is yes; when a peice is undefined that usually puts a damper on things

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry, I meant when any of those 3 are 0.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1Q(x) cant be zero; and R(x) cant be zerp

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1zerp is like a zero but only got its GED

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0S(x) can't be zero either though, because if it were, S(x)/R(x) would be 0 and that would be dividing the first part by 0, right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry, I got screwed up, I meant it would make S(x)/R(x) undefined and thus the whole thing. Okay, I just wanted to make sure it was any of the 3.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1P(x)  Q(x) < cant be zero  R(x) < cant be zero  S(x) < cant be zero
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