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anonymous

  • 5 years ago

Find the x & y intercepts f(x)=x²-9x+7 please help me

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  1. anonymous
    • 5 years ago
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    \[f(0)=0^2-9\times0+7=7\] which is the y intercept.\[f(x)=0=x^2-9x+7=>x=(9\pm \sqrt{53})/2\]Which are the x intercepts.

  2. anonymous
    • 5 years ago
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    the answer is x-intercept is (8.1,0.9) y-intercept is (0,7) how did they get these answers

  3. anonymous
    • 5 years ago
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    The x intercepts occur when y=0 (or, if you like, f(x)=0) so you just put this into you equation (remember, this is a quadratic function this will have two solutions and the function will therefore have two x intercepts). Similarly, the y intercept occurs when x=0, so you put this into your equation.

  4. anonymous
    • 5 years ago
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    ?

  5. anonymous
    • 5 years ago
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    i know how to do y-intercepts but not x

  6. anonymous
    • 5 years ago
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    X intercepts occur when f(x)=0, so make your equation equal to zero and solve.

  7. anonymous
    • 5 years ago
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    plz show me how

  8. anonymous
    • 5 years ago
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    Do you know how to solve a quadratic equation?

  9. anonymous
    • 5 years ago
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    no

  10. anonymous
    • 5 years ago
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    http://www.purplemath.com/modules/quadform.htm

  11. anonymous
    • 5 years ago
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    i just found a great website that did it for me ty

  12. anonymous
    • 5 years ago
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    Good :)

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