I am working on a double integral of 3xy where R is the region in the first quadrant bounded by x^2+y^2=9, y=4x, y=0.
I drew a picture and I have the inner integral from 4x to sqrt(9-x^2) and the outer integral from 0 to 3-- of 3xy dy dx

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ok- I know I have a problem since my answer is negative (and I'm in the first quadrant)

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