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anonymous
 5 years ago
Find the volume of the region between the graph of f(xy)=36−x^2−y^2 and the xy plane.
I'm not too sure how to set up the double integral but 36x^2y^2 is what we will integrate? right??
anonymous
 5 years ago
Find the volume of the region between the graph of f(xy)=36−x^2−y^2 and the xy plane. I'm not too sure how to set up the double integral but 36x^2y^2 is what we will integrate? right??

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the x will surely go from 0 till 6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or maybe from 6 to 6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok I guess I have an idea

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the level surface of this is always a circle

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when we look at the xy plane it is a circle with center (0,0) and radius 6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so x goes from 6 to 6 and y goes from

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0would we then use x^2 + y^2 = r^2 to solve for y?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{36x ^{2}}\] to \[\sqrt{36x ^{2}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm this cannot be good... damn it would mean that the integral is 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm going to think about it over dinner will be back in 20 min

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, I am going to bed soon
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