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smurfy14

  • 5 years ago

[2x-1]/[(x+2)(x^2+3)]=0 solve the equation.

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  1. anonymous
    • 5 years ago
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    x=1/2

  2. smurfy14
    • 5 years ago
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    how did you get it?

  3. anonymous
    • 5 years ago
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    hold on let me type it out

  4. smurfy14
    • 5 years ago
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    ok

  5. anonymous
    • 5 years ago
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    hold on im going to type it out on word then ill attach it, its just easier

  6. smurfy14
    • 5 years ago
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    alright

  7. myininaya
    • 5 years ago
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    the bottom doesn't make a fraction 0 only the top does so set 2x-1=0 and solve for x 2x=1 x=1/2 but you also have to be careful that this doesn't make the bottom zero since 0/0 does not exsit but you are good the answer is 1/2

  8. smurfy14
    • 5 years ago
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    oh ok but how come you dont do anything to the bottom?

  9. anonymous
    • 5 years ago
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    I have a much longer description lol click on the file i have attached

  10. myininaya
    • 5 years ago
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    the only thing that makes a fraction zero is the top

  11. smurfy14
    • 5 years ago
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    oh ok it makes sense thanks guys :)

  12. smurfy14
    • 5 years ago
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    do either of yall no how to do this one? x^3-2x^2-5x+6=0

  13. anonymous
    • 5 years ago
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    x=1,3,-2

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