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  • 5 years ago

differentiate y=xe^sinx

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  1. myininaya
    • 5 years ago
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    we need product rule but first lets look at e^sinx if we have y=e^sinx if we take natural log of both sides we have lny=lne^sinx lny=sinxlne lny=sinx(1) lny=sinx we use chain rule to find(lny)' y'/y=cosx y'=ycosx y'=e^sinx*cosx so lets go back to y=xe^sinx we need the product rule y'=(x)'e^sinx+x(e^sinx)' y'=1e^sinx+xe^sinx*cosx y'=e^sinx(1+xcosx)

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