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anonymous
 5 years ago
how do i find the points to graph these two linear sentences x+2y<=12 and 3xy>=6? Please show all work.
anonymous
 5 years ago
how do i find the points to graph these two linear sentences x+2y<=12 and 3xy>=6? Please show all work.

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Owlfred
 5 years ago
Best ResponseYou've already chosen the best response.0Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you graph the boundary lines: x+2y = 12 and 3xy = 6

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1pick a point not on the line; (0,0) is an easy testing point

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1and if those make the equation true; then the side with that point is good, shade it; if false, go with the other side

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ah so you can start with any natural number then and plug it into the formula? or no?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you can, but it helps to see that these are line equations; and you just need 2 points to draw a line with right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the lines themselves are boundaries for the inequalities; so graph them first;

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1x+2y = 12 and 3xy = 6; graph these lines so you establish the boundaries for the inequalitites

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1then pick a point that is NOT on the line to test for a result. that point will be on one side or the other of the line right? The most conviennt point to test is the origin: (0,0) x+2y<=12 and 3xy>=6 0+2(0)<=12 and 3(0)(0)>=6 0 <= 12 and 0 >=6 true false

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1all the points that make a true stament get shaded; all th epoints that make it false... shade the other side of the line

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay i get it use typing it out really help me... :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol you* typing it out...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1school comp is slow lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its so weird maybe im asking the wrong question because my book is giving me 2 lines not one for the answer

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the answer has 2 lines; I just demonstrated with 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0o sorry i get it now. i was confused for a second so then i can use the same points (0,0) for the second variable correct?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1more like this yes, as long as (0,0)aint on the line your testing, its the easiest one to use

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1it is the common area that the two have that are solutions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0gd i still am confused so now that we have that one line how do we plot the other line? because in the above answer you plug (0,0) into both variables

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lemme just write this out and see if i can figure it out before i frustrate you.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you really make 2 solution sets and where they overlap, is the area I shaded

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do i give you a good review?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you might have to hit f5 to refresh your browser and youll see a 'good answer' button next to my name

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0know a good free graphing programing?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1hmmm.... i use wolframalpha.com alot ; but it suits me

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=3xy%3E%3D6+and++x%2B2y%3C%3D12
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