anonymous
  • anonymous
represent ln5 as a definite intergral of the reciporcal function y=1/t
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\int\limits_{1}^{5} 1/t \]
anonymous
  • anonymous
how would i grapth that to show the area it represents
anonymous
  • anonymous
well you just need to graph 1/t and the area where x goes from 1 to 5

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anonymous
  • anonymous
how do i enter that in the calc
anonymous
  • anonymous
with a graphic one you can do it. but I never used one
anonymous
  • anonymous
do you know how 1/t looks like?
anonymous
  • anonymous
no :/
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=graph+1%2Fx
anonymous
  • anonymous
the area you need is the one under the graph from x=1 to x=5
anonymous
  • anonymous
so the first one?
anonymous
  • anonymous
practice makes perfect, if you do calculus you need to be able to draw basic graphs of functions
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=graph+1%2Fx+from+1+to+5
anonymous
  • anonymous
so that is the the area? lol do i need to shade anything
anonymous
  • anonymous
shade under the graph until the x axes
anonymous
  • anonymous
perfect thanks
anonymous
  • anonymous
what is the x-intercept of the tangent to y=e^x at x=45
anonymous
  • anonymous
hmm, the derivative of e^x is e^x so the tangent at x=45 has slope of e^45 and the actual value is the same so then tangent line is y=e^45+e^45x the x intercept means that y=0 so 0=e^45+e^45x x=-1 that means that from x=45 you need to go back 1 to get the y intercept solution: x=44
anonymous
  • anonymous
okay thats what i got. sweet
anonymous
  • anonymous
well done!!

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