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anonymous

  • 5 years ago

Tricky question! Evaluate if possible. If not, state why. Sin[sin-1<(inverse of sin) 1.1]

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  1. amistre64
    • 5 years ago
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    cant really tell what the problem is stateing

  2. amistre64
    • 5 years ago
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    you might need to rewrite it to clear it up

  3. anonymous
    • 5 years ago
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    Sin[sin-1 1.1]

  4. amistre64
    • 5 years ago
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    \(sin(sin^{-1}(1.1))\) like this?

  5. anonymous
    • 5 years ago
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    correct.

  6. amistre64
    • 5 years ago
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    its just 1.1 then the sin^-1 gives you back an angle, and then the sinfunction translates it back to a ratio. Its like going to the store and then coming back home; you end up where you left

  7. anonymous
    • 5 years ago
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    okay thanks! i have another one.

  8. amistre64
    • 5 years ago
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    is it posted yet?

  9. anonymous
    • 5 years ago
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    no doing it now

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spraguer (Moderator)
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