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anonymous
 5 years ago
I have a Magnitisim question
If a proton is traveling in helical trajectory due to a magnetic field in +Z and a velocity in the x and y direction? I am trying to Find the initial magnetic force on the proton.
anonymous
 5 years ago
I have a Magnitisim question If a proton is traveling in helical trajectory due to a magnetic field in +Z and a velocity in the x and y direction? I am trying to Find the initial magnetic force on the proton.

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Owlfred
 5 years ago
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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0According to the right hand rule, * thumb points in the direction of a moving positive charge's velocity, v * fingers point in the direction of magnetic field, B * palm faces in the direction of the magnetic force, F So, if the magnetic field is along +Z direction, and velocity in x direction, the force will be downwards i.e along Y direction. And if the magnetic field is along +Z direction, and velocity in y direction, the force will be downwards i.e along +X direction. Since the velocities are both in X and Y directions, the force will be in the direction of the 'resultant' of the two direction (i.e Y and +X )

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So, this is basically a case where there is uniform magnetic field in space in the same direction Z. What happens when a proton enters this field? The important point is that when a moving charge enters a magnetic field, it suffers a force \[F = q(v \times B)\] That has the following characteristics: 1. There will be no force in the direction of field. So, there will no change in the component of velocity in the direction of field. That is, the zcomponent of initial velocity will remain same. 2. The other 2 components of velocity (vx and vy) are perpendicular to the field. Whatever be resulting velocity in xy plane, there will be a force that is always perpendicular to it. Whenever, there is a force that is always perpendicular to instantaneousvelocity, this leads to uniform circular motion. So, the particle will go in circles along xy plane. The important part is: *The speed of circular motion (ie, the magnitude of resultant of vx and vy) remains same throughout *The axial force (qvB) will also continue to be same as at initial time. 3. So it continues its movement along the zdirection, while it goes in circles in xy pane. Together, this gives rise to the helical trajectory. So, the initial force you need is F = q (magnitude of resultant of vx and vy) B. ie, \[F = qB \sqrt{v _{x0}^{2} + v _{y0}^{2}}\] where initial velocity is: \[v _{x0} + v _{y0} + v _{z0}\]
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