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carrie14stewart

  • 3 years ago

Simplify the difference b^2-2b-8/b^2+b-2 subtract 6/b-1

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  1. 91rt
    • 3 years ago
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    factorize \[(b ^{2}-2b-8)/(b ^{2}+b-2)\] \[(b ^{2}-2b-8)/(b ^{2}+b-2) = (b=4)(b+2)/(b+2)(b-1)\]

  2. 91rt
    • 3 years ago
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    from there, you can do the subtraction

  3. 91rt
    • 3 years ago
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    it's supposed to be (b-4) and not (b=4) sorry. typo mistake

  4. carrie14stewart
    • 3 years ago
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    so what will my answer be I can do it from there but I wanna make sure I get the right answer! Thank u for ur help I appreciate it!

  5. 91rt
    • 3 years ago
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    you will get (b-10)/(b-1) (:

  6. carrie14stewart
    • 3 years ago
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    Thank u very very much!!!

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