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carrie14stewart
Simplify the difference b^2-2b-8/b^2+b-2 subtract 6/b-1
factorize \[(b ^{2}-2b-8)/(b ^{2}+b-2)\] \[(b ^{2}-2b-8)/(b ^{2}+b-2) = (b=4)(b+2)/(b+2)(b-1)\]
from there, you can do the subtraction
it's supposed to be (b-4) and not (b=4) sorry. typo mistake
so what will my answer be I can do it from there but I wanna make sure I get the right answer! Thank u for ur help I appreciate it!
you will get (b-10)/(b-1) (:
Thank u very very much!!!