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anonymous

  • 5 years ago

if a pig pen has a length that is two more than 4 times the width and the perimeter is 158, what are the dimensions of the pig pen

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  1. anonymous
    • 5 years ago
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    what shape is the pen? rectangular?

  2. anonymous
    • 5 years ago
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    square

  3. anonymous
    • 5 years ago
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    no it cant be a square. it is a rectangle. anyway. do you know the formula for the perimeter of a rectangle?

  4. anonymous
    • 5 years ago
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    that all the info it gave

  5. anonymous
    • 5 years ago
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    okay dont worry about that. tell me if you know the formula for the perimeter of a rectangle

  6. anonymous
    • 5 years ago
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    no

  7. anonymous
    • 5 years ago
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    okay it is 2 * ( width + length)

  8. anonymous
    • 5 years ago
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    so lets call the length L and the width W .

  9. anonymous
    • 5 years ago
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    so what can you tell me about the relationship between L and W from your problem?

  10. anonymous
    • 5 years ago
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    2*6=12+158=170

  11. anonymous
    • 5 years ago
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    the problem states 2 more then 4 times the width and the perimeter is 158

  12. anonymous
    • 5 years ago
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    right

  13. anonymous
    • 5 years ago
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    so the length is 2 more than 4 times the width. If the width is W, then what is L?

  14. anonymous
    • 5 years ago
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    L=4W+2

  15. anonymous
    • 5 years ago
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    P=2(W+L) 158=2(W+4W+2) 158=2W+8W+4 158-4=2W+8W (154=10W) 1/10 15.4=W so thats it, the with of the pigpen is 15.4 to find the length, just use the formula and substitute the width with 15.4 P=2(W+L) 158=2 (15.4+L) 158= 30.8 +2L 158-30.8=2L (127.2=2L)1/2 63.6 = L so the length is 63.6. ^_^

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