anonymous
  • anonymous
if a pig pen has a length that is two more than 4 times the width and the perimeter is 158, what are the dimensions of the pig pen
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
what shape is the pen? rectangular?
anonymous
  • anonymous
square
anonymous
  • anonymous
no it cant be a square. it is a rectangle. anyway. do you know the formula for the perimeter of a rectangle?

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anonymous
  • anonymous
that all the info it gave
anonymous
  • anonymous
okay dont worry about that. tell me if you know the formula for the perimeter of a rectangle
anonymous
  • anonymous
no
anonymous
  • anonymous
okay it is 2 * ( width + length)
anonymous
  • anonymous
so lets call the length L and the width W .
anonymous
  • anonymous
so what can you tell me about the relationship between L and W from your problem?
anonymous
  • anonymous
2*6=12+158=170
anonymous
  • anonymous
the problem states 2 more then 4 times the width and the perimeter is 158
anonymous
  • anonymous
right
anonymous
  • anonymous
so the length is 2 more than 4 times the width. If the width is W, then what is L?
anonymous
  • anonymous
L=4W+2
anonymous
  • anonymous
P=2(W+L) 158=2(W+4W+2) 158=2W+8W+4 158-4=2W+8W (154=10W) 1/10 15.4=W so thats it, the with of the pigpen is 15.4 to find the length, just use the formula and substitute the width with 15.4 P=2(W+L) 158=2 (15.4+L) 158= 30.8 +2L 158-30.8=2L (127.2=2L)1/2 63.6 = L so the length is 63.6. ^_^

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