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hope this helps:D

thank you!

your welcome:D

lets try this:
\[y=y_0e^{kt} \] \[y_0=40\]so you have
\[y=40e^{kt}\]

i love how helpful you are thank you so much

my answer may be off so let me check it

ok

oh wait. quadruples! ok you start counting you have 40

yeah i got 160 when i tried on my own, i just got confused

yeah i got 160 when i tried on my own, i just got confused

yeah i got 160 when i tried on my own, i just got confused

in twenty day s you have 160
in another 20 day you have 640

so where do i plug that in?

so where do i plug that in?

so where do i plug that in?

ok i was right.

everything i wrote was correct.

we can do it the easy way without solving like we did, although that is what they want you to do

first find k, and then replace t by 50

now just replace t by 50 and you get
\[40\times 4^{\frac{50}{20}}=40\times 4^{\frac{5}{2}}\]

\[4^{frac{5}{2}}=\sqrt{4^5}=2^5=32\]

and \[32\times= 1280\]

i meant 32*40=1280

either way that is the correct answer

okay makes sense! thanks again

welcome