[(x)/(x+2)]-[(2)/(2x-1)]=(1/5) please solve thanks!

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[(x)/(x+2)]-[(2)/(2x-1)]=(1/5) please solve thanks!

Mathematics
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one of the solution is -3/4 other one is 3
1 Attachment
how though?

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the solution is in the attachment
thanks!! do you know how to get -3/4 like that iman guy was talking about?
there is a mistake. Im trying to fix it
do you have a graphing calculator?
no but im not allowed to use it on my hw anyways
ok so what u need to do is plug in 1/5 to the y then solve for x!
emunrradtvamg are you talking about the -1 being positive? if so i got it. and imman there is no y?
well 1/5 is basically the y sorry!
1 Attachment
This is where i got
and finally
1 Attachment
im i right?
i dont think thats right lol but the very first one you attached is right. now i just need to figure out how to get -3/4 as the second answer. The correct answer is 3 and -3/4 i just dont know how to show the work for the second answer.
actually the very first attachment is wrong
well you messed up a bit at the end but in the end it is still 3
5x-10=2x-1 3x=9 x=3
Ok. I tried lol
too long to be solved through openstudy
thanks very much! do you how to get -3/4 for the second answer?
I too, am having trouble following the work on the second attachment. Although 3 is a correct solution.
do you know how to get -3/4 radar?
Well the quadratic may have two roots, the 3 and another. I am hung up on the second line of the attachment, where he put the numerator over the LCD and got x(2x+2) I keep getting x(2x-1) for the first fraction. I will look into it further and post here later. Right now I got to put my dogs up.
But first lets see if -3/4 is an answer -3/4 2 1 ------ - --------- = ---- -3/4 +2 2(-3/4)-1 5 -3/4 2 1 ------ - ---------- = ---- 5/4 -5/2 5 -3/5 - (-4/5 = 1/5 It checks as an answer
The solution to that quadratic does not come out to 3 or -3/4. the results of\[x=1/16(3\pm 3\sqrt{65}\] is an irrational number not the integer 3, or the fraction -3/4 something is wrong (maybe with me lol)

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