anonymous
  • anonymous
Could someone please explain how to find the indefinite integral of csc(x) ?
Mathematics
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

Owlfred
  • Owlfred
Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!
watchmath
  • watchmath
\(\csc x=\frac{\csc x(-\csc x+\cot x)}{(-\csc x+\cot x)}\) Now use substitution \(u=-\csc x+\cot x\). Then the integral become \(\int du/u=\ln |u|+C=\ln|-\csc x+\cot x|+C\)
anonymous
  • anonymous
so you have to multiply by a factor of the derivative of csc(x) divided by itself, or 1, to solve?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

watchmath
  • watchmath
Well, first yes we multiply by 1 so it won't change anything. But \(-\csc x+\cot x\) is not the derivative of \(\csc x\). What I can say that we multiply that weird expression just to make it work. How the first person come up with this trick I have no idea :D.
anonymous
  • anonymous
oops i did not take notice of the plus sign between them, now i see, thanks for the explanation

Looking for something else?

Not the answer you are looking for? Search for more explanations.