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hanbru

  • 4 years ago

inverse cosine of square root of 3 over 2? cos-1(square root of 3/2)

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  1. Owlfred
    • 4 years ago
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    Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

  2. myininaya
    • 4 years ago
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    cos(pi/6)=square of 3/2

  3. robtobey
    • 4 years ago
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    \[\text{ArcCos}\left[\frac{\sqrt{3}}{2}\right]=\frac{\pi }{6}\] Am not sure the square root of what was.

  4. myininaya
    • 4 years ago
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    what was?

  5. myininaya
    • 4 years ago
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    oops i missed my word root above

  6. robtobey
    • 4 years ago
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    was the argument of the cosine (square root 3)/2 or square root (3/2)

  7. myininaya
    • 4 years ago
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    i assumed it to be over just the numerator

  8. robtobey
    • 4 years ago
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    Thanks for responding.

  9. myininaya
    • 4 years ago
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    lol everyone needs love

  10. myininaya
    • 4 years ago
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    rob look at the post before this? do you agree with my attachment?

  11. myininaya
    • 4 years ago
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    the post by galaxy

  12. myininaya
    • 4 years ago
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    or i mean thread

  13. robtobey
    • 4 years ago
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    not sure what thread you are referring to. do you have the web address?

  14. myininaya
    • 4 years ago
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    ok you see all the questions right? right underneath this thread by hanbru there is galaxy (if sinx=1/3 and secy=5/4, where x and y lie btw 0 and pi/2, blah blah

  15. myininaya
    • 4 years ago
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    http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4ddf14c3c9a28b0b52ad63c2

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