## anonymous 5 years ago A plane landing at PDX has to descend 1650ft over a diagonal distance of 9700ft. What is the angle of depression of the plane? help would be nicce<33

1. anonymous

$\frac{\text{ArcSin}[1650/9711]}{\pi }180 = 9.78261 \text{ Degrees}$

2. anonymous

oh gotcha thanks!

3. anonymous

Sorry. Entered 9711 and it should have been 9700. Not much difference in the angle. $\frac{\text{ArcSin}[1650/9700]}{\pi }180 = 9.79381 \text{ degrees}$

4. anonymous

Thank you for the medal.

5. anonymous

no prob<3

6. anonymous

myininaya, Here's what I got: $\text{Cos}\left[\text{ArcSec}\left[\frac{5}{4}\right]+\text{ArcSin}\left[\frac{1}{3}\right]\right]=-\frac{1}{5}+\frac{8 \sqrt{2}}{15}$