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immanuelv

  • 5 years ago

if you draw a 5-card hand from a standard deck of playing cards, how many hands could contain exactly 4 cards from the same suit?

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  1. anonymous
    • 5 years ago
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    wait a little confused. does this mean what is the probability you get exactly 4 cards of the same suit?

  2. anonymous
    • 5 years ago
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    watchmath do you understand this question?

  3. anonymous
    • 5 years ago
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    perhaps the answer is \[\dbinom{13}{4}\times \dbinom{39}{1}\times 4\]?

  4. anonymous
    • 5 years ago
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    i don't really know how to intemperate "if you draw a 5-card hand"..."how many hands"

  5. immanuelv
    • 5 years ago
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    that is what i'm trying to figure out!

  6. anonymous
    • 5 years ago
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    well maybe it means how many possible hand have 4 of one suit and two of another. if so, lets start with clubs. you need 4 clubs and 1 non club. the number of ways to get 4 clubs is \[\dbinom{13}{4}\] and the number of ways you can choose one non-club is \[\dbinom{39}{1}\]

  7. anonymous
    • 5 years ago
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    then we do the same for each other suit hence multiply by 4

  8. immanuelv
    • 5 years ago
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    yes.....

  9. immanuelv
    • 5 years ago
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    my theory is 4(13 C4* 39C1)

  10. anonymous
    • 5 years ago
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    that is what i wrote so it looks good to me

  11. anonymous
    • 5 years ago
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    4*13*11*5*39

  12. immanuelv
    • 5 years ago
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    Thank you very much !!

  13. anonymous
    • 5 years ago
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    welcome

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