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anonymous
 5 years ago
The length of a rectangle is 8 cm greater than its width. Find the dimensions of the rectangle is its area is 105 cm^2. Write an equations and solve by factoring.
anonymous
 5 years ago
The length of a rectangle is 8 cm greater than its width. Find the dimensions of the rectangle is its area is 105 cm^2. Write an equations and solve by factoring.

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L
 5 years ago
Best ResponseYou've already chosen the best response.0width = W length = L = W+8 Area = W . L = W . (W+8) = 105 W^2 + 8W = 105 W^2 + 8W  105 = 0 W^2 + 8W  105 = (W+15) . (W7) = 0 > (W+15) = 0 or (W7) = 0 > W = 15 or W = 7 15 is no a metric value, because it is negative So the width is 7cm W = 7cm L = 7+8 = 15cm *
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