anonymous
  • anonymous
how do i factor this out completely? 12y^5-34xy^4+14x^2y^3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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gw2011
  • gw2011
You can first factor out 2y^3 and you get: 2y^3(6y^2-17xy+7x^2) Rearranging this slightly only because I like putting x first and because the middle term -17xy has x first: 2y^3(7x^2-17xy+6y^2)-- Now (7x^2-17xy+6y^2) can also be factored: 2y^3(7x-3y)(x-2y) This is the factor
anonymous
  • anonymous
\[2y ^{3}[(2y-x)(3y-7x)]\]

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